Practica Matematica 1

UNIVERSIDAD AMERICANA

INGENIERÍA INFORMÁTICA

MATEMATICA 1

TAREA N° 1

fabiola monge

JULIO, 2010

la capacidad del bidón.

1/8x+38 = 3/5x

Resolver las ecuaciones de primer grado.

2x = 6

X= 6⁄2

X= 3

2x-3 = 6+x

2x – x = 6 + 3

X = 9

2(2x-3) = 6 + x

4x-6 = 6+x

4x-x = 6+6

3x = 12

X = 12⁄3

X = 4

(x-1)/6 – (x+3)/2 = -1

(x-1-3(x+3))/6 = 6/6

X -1-3x-9 = -6

-2x = -6+1+9

X = 4/(-2)

X = -2

3/4(2x+4) = x+19

3/2 x+3 = x+19

3/2 x-x = 19-3

x/2 = 16

X = 32

4(x-10) = -6(2-x) -6x

4x-10 = -12+6x-6x

4x-6x+6x = -12+40

4x = 28

X = 7

2(x+1)-3(x-2) = x+6

2x+2-3x+6 = x+6

2x-3x-x = 6-2-6

-2x = -2

X = 1

(x-1)/4 – (x-5)/36 = (x+5)/9

(9(x-1)-(x-5))/36 = (4(x+5))/36

9x-9-x+5 = 4x+20

9x-x-4x = 20+9-5

4x = 24

X = 6

(3x+1)/7 – (2-4x)/3 = (-5x-4)/14+7x/6

(6(3x+1)-14(2-4x))/42 = (3(-5x-4)+49x)/42

18x+6-28+56x = -15x-12+49x

18x+56x-49x+15x = -12-6+28

40x = 10

X = 1/4

5/(x-7) = 3/(x-2)

(5(x-2))/((x-7)(x-2)) = (3(x-7))/((x-7)(x-2))

5x-10 = 3x-21

5x-3x = -21+10

2x = -11

X = (-11)/2

4/(x-3) = 5/(x-2)

(4(x-2))/((x-3)(x-2)) = (5(x-3))/((x-3)(x-2))

4x-8 = 5x-15

4x-5x = -15+8

-x = -7

X = 7

6((x-1)/8-(2x-3)/16) = 3(3x/4-1/4)- 6(3x-2)

6((2x-2-2x+3)/16)= 3((3x-1)/4)- (9x+6)/8

6 . 1/6 = (9x-3)/4 - (9x+6)/4

3/8+(9x-6)/8 = (9x-3)/4

(9x-3)/2 = 9x-3

9x-3 = 2(9x-3)

9x-3 = 18x-6

-3+6 = 18x-9x

3 = 9x

1/3 = x

2-[-2(x+1)- (x-3)/2] = 2x/3-(5x-3)/12+3x

2-[-2x-2- (x-3)/2] = (8x-5x+3+36x)/12

2+2x+2+(x-3)/2 = (39x+3)/12

(5+5x)/2 = (13x+1)/4

5+5x = (13x+1)/2

10+10x = 13x+1

10x-13x = 1-10

-3 x= -9

X = 3

2/3[x-(1-(x-2)/3)]+1 = x

2/3[x-1+(x+2)/3]+1 = x

2x/3-2/3+2x/3+1 = x

2x/3+2x/3-x = -1+2/3

x/3 = (-1)/3

X = -1

2-[-2(x+1)- (x-3)/2] = 2x/3-(5x-3)/12+3x

2-[-2x-2- (x-3)/2] = (8x-5x+3+36x)/12

2+2x+2+(x-3)/2 = (39x+3)/12

(5+5x)/2 = (13x+1)/4

5+5x = (13x+1)/2

10+10x = 13x+1

10x-13x

...