Tarea de Resistencia de materiales 2

Asignatura:

Resistencia de Materiales

Tema:

                        Diagrama de Cortante y Momento

Fecha:      6 de Marzo de 2015

Determinar las reacciones en los opoyos y determine y dibuje los diagramas de cortante y  momentos de la figura mostrada a continuacion:

[pic 1]

Desarrollo

[pic 2]

[pic 3]

(W1* 1) + (RAx * 0) + (Ray * 0) – (F1 * 2.50) – (W2 * 5.50) + (RBy * 7.50) – (F2 * 9.5) = 0

(20 * 1) + 0+0 – (8*2.50) – (8*5.50) + 7.5RBy – (5*9.5) = 0

14 -20 -44 + 7.5RBy – 47.5 = 0

RBy = 91.5 / 7.50

RBy = 12.2 ton

[pic 4]

∑Fy = 0 +

-W1 + RAy - F1- W2+ RBy - F2 = 0

-20 + RAy – 8 – 8 + 12.2 – 5 = 0

RAy = 28.8 ton

[pic 5]

[pic 6]

[pic 7]

Mo = 0

M1 = M0 –A1 = 0 –(0.5* 14* 3.5) = -24.5 Ton*m

M2 = M1 + A2 = -24.5 +0.5 (14.8 + 8.8)* 1.5 = -6.8 Ton*m

M3 = M2 + A3 = -6.8 + (8.8 * 1) =  2 Ton*m

M4 = M3 + A4 = 2 + (0.8* 1) = 2.8 Ton*m

M5 = M4 + A5 = 2.8 + (0.5 * 0.4*0.8) = 2.96 Ton*m

M6 = M5 - A6 = 2.96 – (0.5 *3.60 * 7.2) = -10 Ton * m

M7 = M6 + A7 = - 10 + (5* 2) = 0.00 Ton* m

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