Hidraulica De Tuberias

SECCIÓN RECTANGULAR

Primer Tramo

Q= 0.529 A=b.y

N= 0.040 P=b+2y

S= 0.016

Y= 0.90b

2. Q. n = A5/3

2(0,529).(0,040) = (b 0,90b)5/3

0.3345 = (0.90b2)5/3

0.3345 = (0.90b2) 5/3

0.3345 = 0.90b10/3

0.3345 = 0.4737b10/3-2/3

0.4737b8/3 = 0.3345

b= 0.3345)

b = 0.395

y = 0.90 0.395

y = 0.355

A = b.y

A = 0,395 0.355

A = 0.140

P = b+2y

P = 0.395+ 2(0.355)

P = 1.105m

RH =

RH =

RH = 0.126m

V = RH2/3xS1/2

V = (0.126) 0.66 x (0.004)0.5

V = 0.402 m/seg

NOFroud = V D = A = 0.140 =0.354

NOFroud = 0.402

NOFroud = 0.362

NOReinold = V x RH

NORe = (0.402)(0.126)

NORe = 56721.16 Turbulento.

SECCION TRAPEZOIDAL

Primer Tramo

Q = 0.529

n = 0.040

Z = 2

Y = 0.90b

S = 0.01b

2. Q.n = A5/3

2(0.529)(0.040) = ((b+2(0.90b)x0.90b))5/3

0.3345 = ((b+1.8b) x (0.9))5/3

0.3345 = (0.90b2+1.62b2)5/3

0.3345 = (2.52b2)5/3

0.3345 = 2.252b10/3

0.3345 = 0.5015b10/3-b2/3

0.3345 = 0.5015b5/3

b = b = 0.3396 m

Y

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