Inventarios

SOLUCION

TAMAÑO DE LOTE COSTO ORDENAR COSTO DE MANTENER COSTO TOTAL

5 1440 57.5 1.463

10 720 115 3.715

15 480 172.5 3.772,5

20 360 230 3.830

25 288 287.5 3887,5

30 240 345 3.945

35 205,7 402,5 4.002,25

40 180 460 4.060

80 90 920 4.520

1. LOTE 5:

COSTO DE DE ORDENAR = O* (D/L) = 10 * (720/5) = 10*144 = 1440

COSTO DE MANTENER = (T*C) * (L/2) = (0.25*92) * (5/2) = 23*2.5 = 57.5

COSTO TOTAL = O * (D/L) + (T*C) * (L/2) = 10 * (720/5) + (0.25*92) * (5/2) = 10 * 144 + 23 = 1463

2. LOTE 10:

COSTO DE ORDENAR = 10 * (720/10) = 10*72 = 720

COSTO DE MANTENER = (0.25*92) * (10/2) = 23*5 = 115

COSTO TOTAL = 10*(720/10)+(0.25*92)*(10/2) = 10*72+23*5 = 3715

3. LOTE 15:

COSTO DE ORDENAR = 10*(720/15) = 10*48 = 480

COSTO DE MANTENER = (0.25-92)*(15/2) = 23*7.5 = 172.5

COSTO TOTAL = 10*(720/15)+(0.25*92)*(15/2) = 10*48+23*7.5 = 3772.5

4. LOTE 20:

COSTO DE ORDENAR = 10*(720/20) = 10*36 = 360

COSTO DE MANTENER = (0.25*92)*(20/2) = 23*10 = 230

COSTO TOTAL = 10*(720/20)+(0.25*92)*(20/2) = 10*36+23*10 = 3830

5. LOTE 25:

COSTO DE ORDENAR = 10*(720/25) = 10*28.8 = 288

COSTO DE MANTENER = (0.25*92)*(25/2) = 23 * 12.5 = 287.5

COSTO TOTAL = 10*(720/25)+(0.25*92)*(25/2) = 10*28.8+23*12.5 = 3887.5

6. LOTE 30:

COSTO DE ORDENAR = 10 *(720/30) = 10* 24 = 240

COSTO DE MANTENER = (0.25*92)*(30/2) = 23 * 15 = 345

COSTO TOTAL = 10*(720/30)+(0.25*92)*(30/2) = 10*24+23*15 = 3.945

7. LOTE 35:

COSTO DE ORDENAR = 10*(720/35) = 10* 20.57 = 205,7

COSTO DE MANTENER = (0.25*92)*(35/2) = 23 * 17.5 = 402.5

COSTO TOTAL = 10*(720/35)+(0.25*92)*(35/2) = 10*20.57+23*17.5 = 4.002,25

8. LOTE 40:

COSTO DE ORDENAR = 10*(720/40) = 10*18 = 180

COSTO DE MANTENER = (0.25*92)*(40/2) = 23*20 =460

COSTO TOTAL = 10*(720/40)+(0.25*92)*(40/2) = 10*18+23*20 =4.060

9. LOTE 80:

COSTO DE ORDENAR = 10*(720/80) = 10*9 = 90

COSTO DE MANTENER = (0.25*92)*(80/2) = 23*40 = 920

COSTO TOTAL = 10*(720/80)+(0.25*92)*(80/2) = 10*9+23*40 = 4.520

1. Analizando los resultados de los costos de los lotes el de menor costo es el lote 15 ya que genera menos costos totales

2. a. (EOQ) = (200*O D) / (T C)

(EOQ) = (200*10*360) / (25*8)

EOQ = 720.000/200 = 3600

EOQ = 3600

EOQ=60

EOQ = (2*10*360) / (0.25*8)

EOQ = 7200/2

EOQ = 3600

EOQ = 60

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