Resistencia total, tabajo colaborativo unad.
Enviado por Abiigaiil.93 • 28 de Marzo de 2017 • Trabajo • 424 Palabras (2 Páginas) • 128 Visitas
[pic 1]
RE1 = R15+R16+R17 = 100 +10 + 3.3k = 113,3 Ω
[pic 2]
RE2 = R13+R14= 1000+100 = 1100 Ω
[pic 3]
RE 3= RE1 * RE2 = 113.3 * 1100 = 124.630 = 102,74 Ω
RE1 + RE2 113.3 + 1100 1.213,3
RE 3= 102,74 Ω
[pic 4]
RE 4= R11 + R12 = 12+ 220 = 232 Ω
RE 4= 232 Ω
[pic 5]
RE 5= RE3 * RE4 = 102,74 * 232= 23.835 = 0,07Ω
RE3 + RE4 102,74 + 232 334.74
RE 5= 0,07kΩ
[pic 6]
RE 6 = R8 + R9+ R10
RE 6 = 2.2 + 4.7 + 4.7 = 11,6 kΩ
[pic 7]
RE 7 = RE5 * RE6 = 0,07* 11,6 = 0,81 = 0,06Ω
RE5 + RE6 0,07+ 11,6 11,67
RE 7 = 0,06 kΩ
[pic 8]
RE8= R5 * R6 = 510 * 510 = 260100 = 255
R5 + R6 510 + 510 1020
RE8= 255Ω
[pic 9]
RE 9 = RE 7 + RE 8 = 255+ 0,06 =255,06
RE 9= 255,06
[pic 10]
RE 10 = R4 + R7 = 560+ 68 = 628Ω
RE 10 = 628Ω
[pic 11]
RE 11 = RE 10 *RE 9 = 628* 255= 160.140 = 0,181
RE 10 + RE 9 628+ 255 883
RE11 = 0,181
[pic 12]
R12 = R2+ R3 = 330 + 120 = 450
R12= 450
[pic 13]
RE 13 = RE 12 *RE 11 = 450* 0,181= 81,45 = 0,180
RE 12 + RE 11 450+ 0,181 450,181
RE13 = 0,180
[pic 14]
RE 14 = R1+ RE13 = 22+ 0,180
RE 14 = 22,18
[pic 15]
R= V/I 5/22,18 Corriente total = 0,22
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