CALCULA EL ÁREA DE LA REGIÓN QUE SE INDICA
Enviado por scottstark • 11 de Marzo de 2013 • Tarea • 969 Palabras (4 Páginas) • 440 Visitas
CALCULA EL ÁREA DE LA REGIÓN QUE SE INDICA . ELIGE LA OPCIÓN CON LA RESPUESTA CORRECTA
OBTÉN EL ÁREA DE LA REGIÓN LIMITADA POR LA CURVA y=4x-x^2 Y EL EJE X Y LAS RECTAS X=2 Y X= 3
X Y
0 0
1 3
2 4
3 3
4 0
.5*3= 1.5
.5*3.5=1.75
.5*3.5=1.75
.5*3=1.5
Suma total: 6.5
Áreas externas.
.5*1/2=0.25
.5*.5/2=0.125
.5*.5/2=0.125
.5*1/2=0.25
Suma de las áreas internas como externas = 7.25
x y
-2 -8
-7/4 -5.3593
-6/4 -3.375
-5/4 -1.9531
-1 -1
-3/4 -0.1218
-2/4 -0.125
-1/4 -0.0156
0 -0
¼ 0.0156
2/4 0.125
¾ 0.4218
1 1
¾ 1.9531
6/4 3.375
7/4 5.3593
2 8
9/4 11.3906
10/4 13.625
3 27
CALCULA EL ÁREA DE LA REGIÓN LIMITADA POR LA CURVA y=x^3, EL EJE Y LAS RECTAS X=-2 Y X=3
(-5.3593)( 1/4 )=1.3398
(-3.375)( 1/4 )=0.84375
(-1.9531)( 1/4 )=-0.4882
(-1)( 1/4 )=-0.25
(-0.1218)( 1/4 )=-0.0304
(-0.125)( 1/4 )=-0.0312
(-0.0156)( 1/4 )= -0.039
total:-3.0992
(-8)( 1/4 )=-2
(-5.3593)( 1/4 )=-1.3398
(-3.375)( 1/4 )=-0.84375
(-1.9531)( 1/4 )=-0.4282
(-1)( 1/4 )=-0.25
(-0.1218)( 1/4 )=-0.0304
(-0.125)( 1/4 )=-0.0312
(-0.0156)( 1/4 )=-0.039
Total: -5.04
(0.0156)( 1/4 )=6.039
(0.125)( 1/4 )=0.0312
(0.4218)( 1/4 )=0.0304
(1)( 1/4 )=0.25
(1.9531)( 1/4 )=0.64882
(3.375)( 1/4 )=0.843.75
(3.3593)( 1/4 )=1.3398
(8)( 1/4 )=2
(11.3906)( 1/4 )=2.84765
(15.625)( 1/4 )=3.9062
(20.7968)( 1/4 )=5.1992
(0.125)( 1/4 )=0.0312
(0.4218)( 1/4 )=0.304
(1)( 1/4 )=0.25
(1.9531)( 1/4 )=0.0482
(5.375)( 1/4 )=0.8437
(5.3593)( 1/4 )=1.3598
(8)( 1/4 )=2
(11.3906)( 1/4 )=2.8476
(15.625)( 1/4 )=3.9062
(20.7968)( 1/4 )=5.1992
(27)( 1/4 )=6.25
Total: 23.5102
Total : 16.7998
X Y
0 0
0.314 0.308
0.628 0.587
0.942 0.808
1.256 0.950
1.57 0.999
1.884 0.951
2.198 0.809
2.512 0.588
2.826 0.310
3.14 0.0
3.454 -0.307
3.768 -0.586
4.082 -0.994
4.396 -0.950
4.71 -0.999
5.024 -0.951
5.338 -0.810
5.652 -0.590
5.966 -0.311
6.28 0.0
3- CALCULA EL ÁREA DE LA REGIÓN LIMITADA POR LA CURVA Y= SEN X Y EL EJE X EN EL INTERVALO [0,2π]
A rect1=0.314 x 0.308=0.096
A rect2=0.314 x 0.587=0.184
A rect3=0.314 x 0.808=0.253
A rect4=0.314 x
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