Molecular Reaction Dynamics
Enviado por ElMadamo • 8 de Marzo de 2013 • 279 Palabras (2 Páginas) • 371 Visitas
Reactions occur because atoms/molecules collide and interact with each other
Collision theory relates rates of gas phase reactions to their rate
Basis is that, for bimolecular reactions, products are formed only if the collision is sufficiently energetic
Consider a simple reaction : A + B -> P
Rate : v = k[A][B]
Second order reaction
Rate constant dependent on a number of physical requirements relting to the collisions which occur
Rate of collisions- reaction rate a rate of collisions
Related to the mean molecular speed c (c a (T/M)0.5) ,M is the molar mass
If s is the collisional cross sectio, then
v a s (T/M)0.5NANB a s (T/M)0.5[A][B] or k a s (T/M)0.5
Energy - a minimum kinetic energy is required for a successful collision, thus a Boltzman factor must be included in the rate constant
k a s (T/M)0.5{exp(-Ea/Rt)}
Finally, molecules may need to collide in a particular orientation, so a steric factor, P, needs to be applied or
k a Ps (T/M)0.5{exp(-Ea/Rt)}
Thus, the form of rate constant: k a steric factor x encounter rate x minimum energy requirement
Each of these factors will now be considered
Collision density (ZAB) = # of collisions/volume/time
Units: m-3 s-1
Related to the collision frequency, z, discussed in section of gases (Chapter 1)
ZAB = s (8kT/πµ)0.5Na 2[A][B]
s = collision cross section = πd2; d =1/2(dA +dB)
Area subtended by a circle of diameter, d
Assumes elastic hard spheres ( see next page)
Na is Avagodro’s number
Na[A] is the number density of A
µ is the reduced mass = (mAmB)/(mA + mB)
If A=B, ZAB = s (4kT/πµ)0.5Na 2[A]2
Reduced by 1/2 because you would double count collisions
Collision densities can be large - N2 @RT Z= 5 x 10 34 m-3 s-1 (d = 280 pm)
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