Desarrollo ejercicios de quimica
Enviado por Esteban Huerta • 14 de Junio de 2017 • Práctica o problema • 1.232 Palabras (5 Páginas) • 278 Visitas
Desarrollo
- V = K [A] [B] [C]
[pic 1][pic 2][pic 3]
= 4,0 x m/s 3,0M 2,0 M 1,0 M[pic 4][pic 5]
= 4,0 x m/s 1,0M 2,0 M 1,0 M[pic 6][pic 7]
0 = [pic 8]
m = 0
1[pic 9][pic 10]
= 3,6 x m/s 4,0 M 6,0 M 3,0 M [pic 11][pic 12]
= 1,2 x m/s 2,0 M 2,0 M 3,0 M[pic 13][pic 14]
[pic 15][pic 16]
n = 1
= 1,2 x m/s 3,0[pic 17][pic 18]
= 4,0 x m/s 1,0[pic 19][pic 20]
[pic 21][pic 22]
P = 1
V = K [B] [C]
4,0 = K [0,20] [0,10][pic 23][pic 24]
V = 2,0 [B] [C][pic 25]
- = K [pic 26][pic 27][pic 28]
= K [pic 29][pic 30][pic 31]
[pic 32]
[][pic 33][pic 34][pic 35]
[pic 36][pic 37][pic 38]
[pic 39]
[pic 40]
[pic 41]
[pic 43][pic 42]
X[pic 44]
3)5,0 = K [0,10][0,20][pic 45][pic 46]
7,5 K [0,10][0,30] [pic 47][pic 48]
[pic 49]
Y = 1
= K [0,20] [0,40][pic 50]
= 7,5 = K [0,10] [0,30][pic 51][pic 52]
5 [pic 53][pic 54][pic 55][pic 56][pic 57]
2 [pic 58][pic 59][pic 60]
[pic 61]
4 = [pic 62]
X = 2
4)0,5 m/s = K [0,2] [pic 63]
0,5 m/s = K [0,2] 0,16
0,5 m/s = K 0,032
K = 15,625
[pic 64]
V = 1-/1
[pic 65]
[pic 66]
[pic 67][pic 68]
5) = 2,4 ms 0,30 M 0,20 M 0,20 M [pic 69][pic 70]
...