MÉTODO DE REGULA FALSI
Enviado por Angmnmmmm • 9 de Julio de 2019 • Resumen • 406 Palabras (2 Páginas) • 118 Visitas
MÉTODO DE REGULA FALSI
PROBLEMA N°1
Sea f(x) = y empleando el método de Regula Falsi, se pide determinar la raíz más pequeña de la función para Se pide realizar el cálculo con una tolerancia menor a 0.0001.[pic 1][pic 2]
SOLUCIÓN PROBLEMA N°1
Dado f(x) = , [pic 3][pic 4]
Sea: f (-3) = 55.012716 f (4) = -52.308051
Por lo tanto: f (-3) x f (4) 0 = [[pic 5][pic 6][pic 7][pic 8][pic 9]
- Sea i = 0
[pic 10][pic 11]
[pic 12][pic 13]
= 0.588206[pic 14][pic 15]
Luego: f () f () = f (-3) f (0.588206) 0[pic 16][pic 17][pic 18]
[pic 19]
[] = [-3,0.588206][pic 20][pic 21]
- Sea i = 1
[pic 22][pic 23]
[pic 24][pic 25]
= 0.505024[pic 26][pic 27]
Luego: f () f () = f (-3) f (0.505024) 0[pic 28][pic 29][pic 30]
[pic 31]
[] = [-3,0.505024][pic 32][pic 33]
- Sea i = 2
[pic 34][pic 35]
[pic 36][pic 37]
= 0.455622[pic 38][pic 39]
Luego: f () f () = f (-3) f (0.455622) 0[pic 40][pic 41][pic 42]
[pic 43]
[] = [-3,0.455622][pic 44][pic 45]
- Sea i = 3
[pic 46][pic 47]
[pic 48][pic 49]
= 0.427071[pic 50][pic 51]
Luego: f () f () = f (-3) f (0.427071) 0[pic 52][pic 53][pic 54]
[pic 55]
[] = [-3,0.427071][pic 56][pic 57]
- Sea i = 4
[pic 58][pic 59]
[pic 60][pic 61]
= 0.410785[pic 62][pic 63]
Luego: f () f () = f (-3) f (0.410769) 0[pic 64][pic 65][pic 66]
[pic 67]
[] = [-3,0.410785][pic 68][pic 69]
- Sea i = 5
[pic 70][pic 71]
[pic 72][pic 73]
= 0.401558[pic 74][pic 75]
Luego: f () f () = f (-3) f (0.401558) 0[pic 76][pic 77][pic 78]
[pic 79]
[] = [-3,0.401558][pic 80][pic 81]
i | [pic 82] | Error estimado |
0 | 0.588206 | - - - |
1 | 0.505024 | 0.083182 |
2 | 0.455622 | 0.049402 |
3 | 0.427071 | 0.028551 |
4 | 0.410785 | 0.016286 |
5 | 0.401558 | 0.009227 |
6 | 0.396348 | 0.005210 |
7 | 0.393411 | 0.002937 |
8 | 0.391758 | 0.001653 |
9 | 0.390828 | 0.000930 |
10 | 0.390304 | 0.000524 |
11 | 0.390010 | 0.000294 |
12 | 0.389845 | 0.000165 |
13 | 0.389752 | 0.000093 0.0001[pic 83] |
...