Termodinamica

Calcula el trabajo máximo de expansión y compresión de etapa en etapa para 1 g/gmol a temperatura constante de 573 °K y en estas condiciones

P Atm 1 2 3 4 5 6 7 8 9 10

V Ltr 47.1 23.5 15.6 11.75 9.4 7.8 6.7 5.8 5.12 4.7

W=Pop (v2-v1) 1atm = 24.22 cal

Expansión

P= 1(pop) a 2 W=Pop (v2-v1) W=1 (47.1-23.5)=23.6 Atm L X 24.22 cal = 571.592 cal

P= 2(pop) a 3 W=Pop (v2-v1) W=2 (23.5 -15.6)=15.8 Atm L X 24.22 cal =382.676 cal

P= 3(pop) a 4 W=Pop (v2-v1) W=3 (15.6 -11.75)=11.55 Atm L X 24.22 cal =279.741 cal

P= 4(pop) a 5 W=Pop (v2-v1) W=4 (11.75 -9.4)=8.28 Atm L X 24.22 cal =200.5416 cal

P= 5(pop) a 6 W=Pop (v2-v1) W=5 (9.4 -7.8)=8 Atm L X 24.22 cal =193.76 cal

P= 6(pop) a 7 W=Pop (v2-v1) W=6 (7.8 -6.7)=6.6 Atm L X 24.22 cal =159.852 cal

P= 7(pop) a 8 W=Pop (v2-v1) W=7 (6.7 -5.8)=6.3 Atm L X 24.22 cal =152.586 cal

P= 8(pop) a 9 W=Pop (v2-v1) W=8 (5.8 -5.12)=5.44 Atm L X 24.22 cal =131.7568 cal

P= 9(pop) a 10 W=Pop (v2-v1) W=9 (5.12 -4.7)=3.78 Atm L X 24.22 cal =91.5516 cal

Suma=2164.0214 cal

Compresión Compresión Compresión Compresión

P=10(pop) a 9 W=Pop (v2-v1) W=10 (4.7 -5.12)=-4.2 Atm L X 24.22 cal =101.724 cal

P= 9(pop) a 8 W=Pop (v2-v1) W=9 (5.12 -5.8)=-6.12 Atm L X 24.22 cal =148.2264 cal

P= 8(pop) a 7 W=Pop (v2-v1) W=8 (5.8 -6.7)=-7.2 Atm L X 24.22 cal =174.384 cal

P= 7(pop) a 6 W=Pop (v2-v1) W=7 (6.7 -7.8)=-7.7 Atm L X 24.22 cal = 186.494 cal

P= 6(pop) a 5 W=Pop (v2-v1) W=6 (7.8 -9.4)=-9.6 Atm L X 24.22 cal = 232.512 cal

P= 5(pop) a 4 W=Pop (v2-v1) W=5 (9.4 -11.75)=-11.75 Atm L X 24.22 cal =284.585 cal

P= 4(pop) a 3 W=Pop (v2-v1) W=4 (11.75 -15.6)=-15.4 Atm L X 24.22 cal =372.988 cal

P= 3(pop) a 2 W=Pop (v2-v1) W=3 (15.6 -23.5)=-23.7 Atm L X 24.22 cal =574.014 cal

P= 2(pop) a 1 W=Pop (v2-v1) W=2 (23.5 -47.1)=-47.2 Atm L X 24.22 cal=11143.184cal

Suma= 3218.1114 cal

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