Integrating activity math 1
Enviado por azonex • 2 de Octubre de 2015 • Ensayo • 522 Palabras (3 Páginas) • 131 Visitas
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Mathematics 1 Algebra
Integrating activity
Teacher Name: Lic. Arturo Montoya Carrillo
Student name: Eduardo Ramses Giacoman Olivera
Group: 129
Roll number: 21
San Nicolás de los Garza, N.L. a 24 de agosto de 2015
INTRODUCTION
We start With te basic concept of algebra, that is used designed simbols that represent cuantities or numeric values. In the algebra we use diferent tipes of symbols and terms: All the letters and symbols diferent from numbers are called literals or variables.
On this stage we haved saw diferent tipes of operations With polinomials: firstable we saw the powers, that is a short way to represent a multiplication. In the algebra the combination of literals and constants recibe the name of algebraic expression.
There are the teme of the reduction of like terms: terms whose variables and exponents are the same; the exponent can be diferent.
EX: 8ª+7ª+a+11-5b= 16ª-5+11
On this part we haved seen the basic operations With polinomials. This have an important part that is the absolute value: represents the distance between any number and the origin. Seen the adition of polinomials, the substraction of polinomials, where you have to change the sign of the polynomial that is going to be substracted. There are the multiplication of polynomial, there are three types of multiplication:
Monomial With Monomial.
Monomial With polynomial.
Polynomial With polynomial.
Also can be used to find the área of a figure.
To we saw the división of polynomials, there are several tipes of división:
Monomial With Monomial.
Polynomial over Monomial.
Polynomial over polynomial.
Examples of algebraic colloquial language in everyday life.
1.- we do not know the age of a person , we say have " n " years , but we know that our age is less than 20years say , then say , have less than 20 algebraic language that is n -20 .
2.- we noticed that when we go faster from home to school , arrived in less time than that because faster short and vice versa , then we planteams a well-known formula that is t = e / v .
3.- If 10 marbles cost me 35 pesos , how much cost me 15 marbles?
10 marbles = $ 35
15 marbles = $ ? ? = (35 * 15) / 10 = $ 52.5
In algebraic language , we could say : Let X be the price of 1 marble , then we have the following equation :
a) 10 X = 35. The other equation is:
b ) = 15X ; Solving for x- a) are: X = 35/10 ; Substituting this value of X in b ) and we have:
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