Matematicas

Resuelve las siguientes ecuaciones con valor absoluto

b) {6x + 3} = -15

6x + 3 ± 15

6x = - 15 – 3 6x = 15 - 3

6x = 18 6x = 12

x = 3 x = 2

d) {4x – 19} = 7

4x – 19 ± 7

4x = 7 + 19 4x = - 7 + 19

4x = 26 4x = 12

X = 6.5 x = 3

Resuelve

b) (2x + 7)2 = 25

2x + 7 = 5

2x + 7 = ± 5

2x = - 7 + 5 2x = - 7 - 5

2x = - 2 2x = - 12

X = -1 x = -6

d) (x + 9)2 = -36

x + 9 = -6

x + 9 = ± 6

x = - 9 + 6 x = - 9 – 6

x = - 3 x = - 15

Resuelve las ecuaciones escribiendo como un trinomio cuadrado perfecto

x2 – 4x + 4 = 25

x – 2 = √25

x – 2 = 5

x = 5 + 2 x = - 5 + 2

x = 7 x = - 3

x2 + 14x + 49 = 49

x + 7 = √49

x + 7 = 7

x = 7 – 7 x = - 7 - 7

x = 0 x = - 14

f) x2 - 5/4x + - 25/64 = - 121/64

x - 5/8 = - 121/64

x - 5/8 = ± - 11/8

x = 11/8 + - 5/8 x = - - 11/8 + - 5/8

x = - 16/8 x = - - 3/4

Resuelve completando el trinomio cuadrado perfecto

x2 – 6x + 13 = 29

x2 – 6x + 9 = 25

(x – 3)2 = √25

X – 3 = ± 5

X – 3 = 5 x – 3 = - 5

X = 5 + 3 x = - 5 + 3

X = 8 x = - 2

x2 + 8x + 7 = 27

x2 + 8x + 16 = 36

(x + 4)2 = √36

X + 4 = ± 6

X + 4 = 6 x + 4 = - 6

X = 6 – 4 x = - 6 – 4

X = 2 x = -10

x2 + 0.65 = 1.8 x

x2 – 1.8x + 0.81 = 0.16

(x – 0.9)2 = √0.16

X – 0.9 = ± 0.4

X = 0.4 + 0.9 x = - 0.4 + 0.9

X = 1.3 x = 0.5

6. Resuelve empleando la formula general

c)6x2 – 17x -3 = 0

x = (17±√(〖17〗^2-4 (6)(-3)))/12

x = 17 ± √361/12

x = (17+19)/12 x = (17-19)/12

x = 3 x = - 0.16

d)7x2 + 10x + 3 = 0

x = (-10±√(〖10〗^2-4 (7)(3)))/14

x = - 10 ± √16/14

x = (- 10+4)/14 (- 10-4)/14

x = - 0.42 x = - 1

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