El cálculo del presupuesto para construir una represa
Enviado por bellaswan2323 • 8 de Septiembre de 2014 • Tarea • 533 Palabras (3 Páginas) • 228 Visitas
a= (37,0)
Letra Cordenada
A (37,0)
B (20,40)
C (19,40)
D (16,40)
E (0,0)
F (10,0)
G (13,0)
H (16, -5)
I (20, -5)
J (24,0)
L (26,0)
M (27, 0)
Segmento AB:
A= (37- 0) B= (20, 40)
(AB)x= 20-37=- 17
(AB)y= 40-0= 40
C=√(〖-17〗^2+〖40〗^2 )
C= √(289+1600)
C=√1889
C= 43.462
Segmento BC:
B= (20, 40) C= (19, 40)
(BC) x= 19-20=-1
(BC) y= 40-40=0
C=√(1^2+0^2 )
C= 1
Segmento CD:
C= (19, 40) D= (16,40)
(CD) x= 16-19= -3
(CD) y= 40-40= 0
C=3
Segmento DE:
D = (16, 40) E= (0,0)
(DE) x = 0-16= -16
(DE) y = 0 -40= 40
C=√(〖-16〗^2+〖40〗^2 )
C= √(256+1600)
C=√1856
C= 43.081
Segmento EF:
E= (0,0) F = (10, 0)
(EF) x= 10 -0= 10
(EF) y = 0-0 = 0
C= 10
Segmento FG:
F: (10, 0) G = (13, 0)
(FG) x = 13-10= 3
(FG) y= 0-0= 0
C= 3
Segmento GH:
G: (13,0) H= (16-5)
(GI)x = 16-13= 3
(GI) y= -5-0 = -5
C= √(3^2+〖-5〗^2 )
C= √(9+25)
C= √34
C=5.83
Segmento HI
H= (16, -5) I= (20,-5)
(HI) x = 20- 16= 4
(HI) y= -5 –(-5) = 0
C= 4
Segmento IJ:
I: (20, -5) J= (24, 0)
(IJ) x = 24 -20 = 4
(IJ) y = -5-0 = -5
C= √(4^2+〖-5〗^2 )
C=√(16+25)
C= √41
C=6.403
Segmento JL:
J= (24, 0) L= (26, 0)
(JL) x= 27- 24 = 2
(JL) y= 0-0= 0
C=2
SEGMENTO LM
L= (26,0) M= (27, 0)
(LM)x = 27- 26= 1
(LM) y= 0-0= 0
C= 1
SEGMENTO MA:
M= (27, 0) A =(37,0)
(MA) x =37-27= 10
(MA) y= 0-0=0
C= 10
SEGMENTO DF:
D= (16,40) F: (10, 0)
(DF) x= 10- 16= -6
(DF) y= 0-40
C=√(〖-6〗^2+〖-40〗^2 )
C=√(36+1600)
C=√1636
C=30.594
SEGMENTO CL
C= (19, 40) L= (26,0)
(CL) x= 26-19= 7
(CL) y= 0-40= 40
C=√(7^2+〖40〗^2 )
C= √(49+1600))
C=√1649
C=40.607
SEGMENTO MB
M= (27, 0) B= (20, 40)
(MB)x= 20-27= -7
(MB)y= 40- 0=40
C=√(〖-7〗^2+〖40〗^2 )
C= √(49+1600)
C=√1649
C= 40.607
Perímetros
ENROCAMIENTO CORAZON FILTRO ENROCAMIENTO
SEGMENTOS DE =43.081
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