FISICA 1 “ACTIVIDAD DE APLICACIÓN”
Enviado por azulCJ • 28 de Marzo de 2016 • Trabajo • 2.466 Palabras (10 Páginas) • 510 Visitas
FISICA 1
“ACTIVIDAD DE APLICACIÓN”
- F1= 60N a 30° Y
F2=30N a 120°[pic 1]
F resultante F.R.[pic 2][pic 3][pic 4]
[pic 5]
F1x= f1cos= (60 )cos30°= 51.9 120° f2=30N[pic 6][pic 7][pic 8][pic 9]
F2x= f2cos= (30) cos120°= -15.0 f1=60N 30°[pic 10][pic 11][pic 12]
36.9 N X[pic 13]
F1y= f1sen= (60)sen 30°=30[pic 14]
F2y= f2sen=(30)sen120°=25.9[pic 15][pic 16]
55.9N
F resultante= [pic 17]
F resultante= [pic 18]
F resultante =[pic 19]
F resultante= [pic 20]
F resultante= 66.98N
= [pic 21][pic 22]
[pic 23]
[pic 24]
2.
[pic 25]
F1= 100N a 50° F2=135N[pic 26][pic 27]
F2=135N a 140° F.R. 140° [pic 28][pic 29][pic 30]
F1=100N[pic 31][pic 32]
F1x= f1cos=(100) cos 50°= 64.27 50° [pic 33][pic 34]
F2x= f2cos=(135) cos 140°= -103.41[pic 35][pic 36]
-39.13N
F1y=f1senØ= (100) sen 50°= 76.60
F2y=f2senØ= (135) sen 140°= 86.77[pic 37]
163.37N
F resultante= [pic 38]
F resultante = [pic 39]
F resultante= [pic 40]
F resultante=[pic 41]
F resultante= 167.99
= [pic 42][pic 43]
4.1750 N[pic 44]
[pic 45]
3.
F1= 75N a 49°
F2=58N a 139°[pic 46][pic 47][pic 48]
F.R. 139° f2=58N[pic 49][pic 50][pic 51][pic 52]
F1x= f1cosØ= (75) cos 49°= 49.20[pic 53]
F2x= f2cosØ= (58) cos139°= -43.77 49° f1=75N[pic 54][pic 55]
5.43N
F1y=f1senØ= (75) sen 49°= 56.60
F2y= f2senØ= (58) sen 139°=38.05[pic 56]
94.65 N
F resultante= [pic 57]
F resultante= [pic 58]
F resultante= [pic 59]
F resultante=[pic 60]
F resultante= 94.80N
[pic 61]
Ø= 17.45[pic 62]
Ø=86.72°
4.
F1= 62N a 192°[pic 63]
F2=53N a 282 192°[pic 64][pic 65]
F1X= f1cosØ= (62) cos 192°= -60.64 f1=62N[pic 66][pic 67][pic 68][pic 69][pic 70][pic 71]
F2x= f2cosØ= (53) cos 282°= 11.01 282°[pic 72]
-49.63 N f2=53N F.R.
F1y=f1senØ= (62) sen 192°= -12.89
F2y= f2senØ (53) sen 282°= -51.84[pic 73]
-64.73N
F resultante= [pic 74]
F resultante=[pic 75]
F resultante= [pic 76]
F resultante=[pic 77]
F resultante= 81.56N
[pic 78]
Ø=12841[pic 79]
Ø= 52.09°
5.[pic 80]
F1= 43N a 65° f2=87N 155°[pic 81][pic 82][pic 83][pic 84][pic 85][pic 86][pic 87]
F2=87N a 155° f1=43N 65° F.R.[pic 88]
F1x= f1cosØ= (43) cos 65°= 18.17
F2x= f2cosØ= (87) cos 155°= -78.84[pic 89]
-60.67N
F1y= f1senØ= (43) sen 65°=38.97
F2y= f2senØ= (87) sen 155°= 36.76[pic 90]
=75.73N
F resultante= [pic 91]
F resultante= [pic 92]
F resultante=[pic 93]
F resultante= [pic 94]
F resultante= 97.03
[pic 95]
Ø= -1.2411[pic 96]
Ø= 50.45°
6.
f1= 23N a 204°
f2= 63 N a 294°[pic 97]
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