La Presa
Enviado por Adrian_696 • 13 de Julio de 2012 • Tarea • 303 Palabras (2 Páginas) • 656 Visitas
La Presa
Con las coordenadas de cada punto calcula los perímetros y áreas de las 4 partes que forman la presa, también responde las preguntas solicitadas.
Cálculo de Perímetros
Enrocamiento A1
ENROCAMIENTO: A(0,0), B(10,0), C(16,30)
AB =√(〖(0)〗^2+〖(0)〗^2 ) = √(〖(10)〗^2+〖(0)〗^2 ) = √100 = 10
BC = √(〖(10)〗^2+(16 )^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √936 = 30.59
CA = √(〖(16)〗^2+〖(0)〗^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √1156 = 34
PERIMETRO: = 74.59 m
Corazón A2
CORAZON: A(16, -4), B(20, -4), C(24,0), D(26,0), E(19,30), F(16,30), G(10,0), H(13,0)
AB = √(〖(16) 〗^2+〖(20)〗^2 ) = √(〖(-4)〗^2+〖(-4)〗^2 ) = √16 = 4
BC = √(〖(20)〗^2+〖(24)〗^2 ) = √((-4)^2+〖(0)〗^2 ) = √32 = 5.6
CD = √(〖(24)〗^2+〖(26)〗^2 ) =√(〖(0)〗^2+〖(0)〗^2 ) =√4 = 2
DE = √(〖(26)〗^2+〖(19)〗^2 ) =√(〖(0)〗^2+〖(30)〗^2 ) = √949 = 30.8
EF = √(〖(19)〗^2+〖(16)〗^2 ) =√((〖30)〗^2+〖(30)〗^2 ) =√9 = 3
FG = √(〖(16)〗^2+〖(10)〗^2 ) = √(〖(30)〗^2+〖(0)〗^2 ) = √936 = 30.59
GH = √(〖(10)〗^2+〖(13)〗^2 ) = √(〖(0)〗^2+〖(0)〗^2 ) =√9 = 3
HA =√(〖(13)〗^2+〖(16)〗^2 ) = √(〖(0)〗^2+〖(-4)〗^2 ) = √25= 5
PERIMETRO = 83.99 m
Filtro A3
FILTRO: A(26,0), B(27,0), C(20,30), D(19,30)
AB = √(〖(26)〗^2+〖(27)〗^2 ) =√(〖(0)〗^2+〖(0)〗^2 ) = √1 = 1
BC = √(〖(27)〗^2+〖(20)〗^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √949 = 30.80
CD = √(〖(20)〗^2+〖(19)〗^2 ) =√(〖(30)〗^2+〖(30)〗^2 ) =√1 = 1
DA = √(〖(19)〗^2+〖(26)〗^2 ) =√(〖(30)〗^2+〖(0)〗^2 ) = √949 = 30.80
PERIMETRO = 63.6 m
Enrocamiento A4
ENROCAMIENTO: A(27,0), B(37, 0), C(20,30)
AB= √(〖(27)〗^2+〖(37)〗^2 ) = √(〖(0)〗^2+〖(0)〗^2 ) = √100 = 10
BC = √(〖(37)〗^2+〖(20)〗^2 ) =√(〖(0)〗^2+〖(30)〗^2 ) √1189 = 34.48
CA = √(〖(20)〗^2+〖(27)〗^2 ) √(〖(30)〗^2+〖(0)〗^2 ) = √949 = 30.80
PERIMETRO: 75.28 m
Cálculo de Áreas:
Enrocamiento A1
ENROCAMIENTO: A(0,0), B(10,0), C(16,30)
0 0
10 0
16 30
0 0
A= 1/2
Area = 150 m2
Corazón A2
CORAZON: A(16, -4), B(20, -4), C(24,0), D(26,0), E(19,30), F(16,30),
...