Laboratorio de Matemáticas
Enviado por Yeslim Hdz • 20 de Mayo de 2018 • Apuntes • 435 Palabras (2 Páginas) • 104 Visitas
[pic 1] |
Laboratorio de Matemáticas
Nombre: Atziri Nohemi Martinez Flores Materia: Matemáticas |
Grupo: 1°B
Maestra: Olga Esthela Fuentes Martínez
Fecha: 27 de Noviembre del 2017
Ecuaciones lineales
5 + 6x = 2 6x = 2 – 5 6x = -3 X = [pic 2] X = -5 | 3x + 5 (2x – 1) = 8 – 3 (4 – 5x) 3x + 10x -5 = 8 – 12 + 15x 13x -5 = -4 + 15x 13 – 15x = -4 + 5 -2x = 1 X= [pic 3] X = [pic 4] X= | 4b + 1 = -18 4b = -18 – 1 4b= - 19 b= [pic 5] b= 4.75 |
18c – 3 = 0 18c = 0 + 3 18c = 3 C= [pic 6] C= 0.16 | 5 – 2d = 9 -2d = 9 – 5 -2d = 4 d= [pic 7] d = [pic 8] | -3f + 1 = 4 -3f = 4 – 1 -3f = 3 f= [pic 9] f= [pic 10] f = -1 |
-2 – 5g = 0 -5g = 0 + 2 -5g = 2 g= [pic 11] g= [pic 12] g= -0.4 | 5s + (4 – s) = 9 5s + 4 – s = 9 4s – 4 = 9 4s = 9 + 4 4s = 13 S = [pic 13] S = 3.25 | |
8 ( 6f – 14) – 7 (12 – 5f) + (23f – 2) – ( 2f + 65) = 0 48f – 112 – 84 + 35f + 23f + 2 – 2f – 65 = 0 48f + 35f + 23f – 2f – 112 – 84 + 2 – 65 = 0 104f – 259 = 0 104f =0 + 259 104f = 259 F = [pic 14] F = 2.490 | 2 (b + 2) -5 (2b – 3) = 3 2b + 4 – 10b + 15 = 3 -8b + 19 = 3 -8b = 3 – 19 -8b = -16 b = [pic 15] b= 2 | |
2 – { k - [ 6k – (1 – 2k) ] } = 100 2 – { k –[ 6k - 1 – 2k ] } = 100 2 –{ k – 6k + 1 + 2k } = 100 2 – {7k + 1} = 100 2 – 7k – 1 = 100 -7k – 1 + 2 = 100 -7k + 1 = 100 -7k = 100 – 1 -7k = 99 K= [pic 16] K = [pic 17] K = 14.1428 | Q – 3 + 6q – 9 + 12q – 15 = 9 Q + 6q + 12q – 3 – 9 – 15 = 9 19q – 27 = q 19 q – q = 27 18q = 27 q = [pic 18] q = 1.5 | |
(3t – 1 ) + 7 = 8t – (3 – 2f) 3t – 1 + 7 = 8t – 3 + 2f 3t + 6 = 10t – 3 3t – 10t = -3 -6 -7t = -9 t = [pic 19] t = [pic 20] | 3-(8v – 5)+(6 – 7v) – 1 = 7 – (v-1)+(4v +4) 3 – 8v + 5 + 6 – 7v -1 = -v +1+4v+4 -8v-7v+3 +5+6-1=-v+4v+7+1+4 -15v+13=3v+12 -18v=-1 V=[pic 21] V= [pic 22] V= 0.1 | |
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