Prueba N°2 Circuitos Corriente Continua

Prueba N°2 Circuitos Corriente Continua.        

Ecuaciones LKC.

La suma de todas las corrientes de entrada es igual a la suma de todas corrientes de salida.

Nodo N°A

I1= I2+I3

Nodo N°B

I3=I4+I5

Nodo N°C

I5=I6+I7

Nodo N°D

I7=I8+I9

Ecuaciones LKV.

Maya N°1                        MAYA N°2

24-I1R1-I2R2-I2R3=0                I2R2+I2R3-I3R4-I4R6-I4R7=0

24-12I1-18I2=0                        18I2-200I3-520I4=0

MAYA N°3                                MAYA N°4

I4R7+I4R6-I5R8-I7R10-I7R11=0                I7R11+I7R10-I6R12-R13I8=0

520I4-190I5-910I6=0                        910I6-1000I7-2200I8=0

MAYA N°5                                        METODO UTILIZADO PARA ENCONTRAR                                                     CORRIENTES GAUS JORDAN MATRIZ 9X9.

I8R13-I9R14-R15I10=0                                 PROGRAMA UTILIZADO DE INTERNET.

220I8-1200I9=0

CORRIENTES DE NODOS.

I1=815.7                                 I9=2.4

I2= 788.1

I3=27.6

I4=16.7

I5= 11

I6= 7.2

I7=3.7

I8=1.3

MAYA N°1

V1=I1XR1     VI= 815.7X12= VI= (815.7/1000)X12=0.815AX12Ω=9.78V

V2=I2XR2      V2=788.1mAX 10Ω=(788.1/1000)X10Ω=0.7881AX10Ω=7.9V

V3=I2XR3      V3= 7881.1mAX8Ω=(788.1/1000)X8Ω= 0.7881AX8Ω=6.3V

MAYA N°2

V4=I3XR4       V4= 27.6mAX200Ω=( 27.6mA/1000)X200Ω=0.0276AX200Ω=5.2V

V6=I4XR6        V6=16.7mAX420Ω=(16.7/1000)X420Ω=0.0167AX420Ω=7.014V

V7=I4XR7         V7= 16.7mAX100Ω=0.0167AX100Ω=1.67V

MAYA N°3

V8=I5XR8        V8= 11mAX190Ω= (11mA/1000)X190Ω=0.011X190Ω=2.09V

V10=I6XR10        V10= 7.2mAX600Ω=(7.2mA/1000)X600Ω=0.0072AX600Ω=4.32V

V11=I6XR11        V11=7.2mAX310Ω=0.0072AX310Ω=2.23V

MAYA N°4

V12=I7XR12        3.7mAX1000Ω=(3.7mA/1000)X1000Ω=3.7V

V13=I8XR13        1.3mAX2200Ω=(1.3mA/1000)X2200=2.86V

MAYA N°5

V14=I9XR14        2.4mAX480Ω=(2.4mA/1000)X480Ω=0.0024x480Ω= 1.152V

V15=I9XR15        0.0024AX720Ω=1.728V

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