Serie De Lyman
Enviado por mariomora • 23 de Septiembre de 2014 • 493 Palabras (2 Páginas) • 298 Visitas
EL ESPECTRO ELECTROMAGNETICO.
SERIE DE LYMAN
1.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 )
E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(7^2- 1^2) )/((7^2 〖)(1〗^2)) J
E=(1.050192x〖10〗^(-16))/49 J E= 2.14324898X〖10〗^(-18) J (1J )/(1.6x〖10〗^(-19) eV)
E=13.39530612 eV
2.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(6^2- 1^2) )/((6^2 〖)(1〗^2)) J
E= (7.65765x〖10〗^(-17))/36 J E=2.127125x〖10〗^(-18) J (1J )/(1.6x〖10〗^(-19) eV)
E=13.29453125 eV
3.- E= (hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(5^2- 1^2) )/((5^2 〖)(1〗^2)) J
E=(5.25096x〖10〗^(-17))/25 J E=2.100384x〖10〗^(-18)J (1J )/(1.6x〖10〗^(-19) eV)
E=13.1274 eV
4.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(4^2- 1^2) )/((4^2 〖)(1〗^2)) J
E=(3.28185x〖10〗^(-17))/16 J E= 2.05115625x〖10〗^(-18)J (1J )/(1.6x〖10〗^(-19) eV)
E=12.81972656 eV
5.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(3^2- 1^2) )/((3^2 〖)(1〗^2))J
E=(1.75032x〖10〗^(-17))/9J E=1.9448x〖10〗^(-18)J (1J )/(1.6x〖10〗^(-19) eV)
E=12.155 eV
6.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(2^2- 1^2) )/((2^2 〖)(1〗^2))J
E=(6.5637x〖10〗^(-18))/4J E=1.640925x〖10〗^(-18)J (1J )/(1.6x〖10〗^(-19) eV)
E=10.25578125 eV
SERIE DE BALMER
1.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(7^2- 2^2) )/((7^2 〖)(2〗^2))J
E=(9.84555x〖10〗^(-17))/196 j E= 5.023239796x〖10〗^(-19)J (1J )/(1.6x〖10〗^(-19) eV)
E=3.139524872 eV
2.- E=(hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(6^2- 2^2) )/((6^2 〖)(2〗^2))J
E=(7.00128x〖10〗^(-17))/144J E= 4.862x〖10〗^(-19)J (1J )/(1.6x〖10〗^(-19) eV)
E=3.03875 eV
3.-E= (hcR_(h (n_i^2 ┤-├ n_f^2 ) ))/(n_i^2 )(n_f^2 ) E=((6.63x〖10〗^(-34) j/s)( 3x〖10〗^8 m/s)(1.1x〖10〗^7 m^(-1) )(5^2- 2^2) )/((5^2 〖)(2〗^2))J
E=(4.59459x〖10〗^(-17))/100J E=4.59459x〖10〗^(-19)J (1J )/(1.6x〖10〗^(-19)
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