CÀLCULO DIFERENCIAL E INTEGRAL

[pic 1]

LCP. Y MAP. PATRICIA GODOY FALCÓN MATRICULA: 147032

GRUPO: IA68

MATERIA: CÀLCULO DIFERENCIAL E INTEGRAL MAESTRO: SERGIO RAÙL LÒPEZ NIETO ACTIVIDAD DE APRENDIZAJE II. REGLAS DE DIFERENCIACIÒN DE FUNCIONES TRIGONOMETRICAS, EXPONENCIALES Y LOGARITMICAS.

VILLAHERMOSA, TABASCO 11 DE JUNIO DE 2021

1)        = [pic 2] − cos[pic 3][pic 4][pic 5][pic 6][pic 7][pic 8][pic 9]

[pic 10]

´ =        (        − cos ( ))

[pic 11][pic 12][pic 13]

([pic 14] +        ) =        ([pic 15]) +        ( )

[pic 16][pic 17]

´ =        (        ) −        (cos ( ))

´ = 2   −        (cos ( ))[pic 18][pic 19][pic 20][pic 21][pic 22][pic 23][pic 24][pic 25][pic 26][pic 27][pic 28][pic 29][pic 30][pic 31][pic 32][pic 33][pic 34][pic 35][pic 36][pic 37][pic 38]

´ = 2 − (− sin ( ))[pic 39][pic 40][pic 41]

´ = 2 + sin( )[pic 42][pic 43][pic 44]

2)        = 1 + sin        − tan[pic 45][pic 46][pic 47]

[pic 48]

´ =        (1 + 7 sin( ) − tan( ))

´ =        (1) +        (7 sin( )) −        (tan( ))[pic 49][pic 50][pic 51][pic 52][pic 53][pic 54][pic 55][pic 56][pic 57][pic 58][pic 59][pic 60][pic 61][pic 62][pic 63][pic 64][pic 65]

´ = 0 +        (7 sin( )) −        (tan( ))[pic 66][pic 67][pic 68][pic 69][pic 70][pic 71][pic 72][pic 73][pic 74]

´ = 0 + 7 cos( ) −        (tan( ))[pic 75][pic 76][pic 77][pic 78][pic 79][pic 80]

´ = 0 + 7 cos( ) − sec( ) ² 7 cos( )³ − 1[pic 81][pic 82][pic 83][pic 84]

´ =[pic 85][pic 86]

cos( ) ²[pic 87]

7 cos ( )³ − 1[pic 88]

´ =[pic 89][pic 90]

cos ( )²[pic 91]

3)        =        sin[pic 92][pic 93][pic 94]

[pic 95]

´ =        (        sin( ))

´ =        ( )ˣ sin( ) +        (sin( ))[pic 96][pic 97][pic 98][pic 99][pic 100][pic 101][pic 102][pic 103][pic 104][pic 105][pic 106][pic 107][pic 108][pic 109][pic 110][pic 111]

´ = 1 sin( ) +        (sin( ))[pic 112][pic 113][pic 114][pic 115][pic 116][pic 117][pic 118]

´ = 1 sin( ) + [pic 119] cos( )[pic 120][pic 121][pic 122]

´ = sin( ) + [pic 123] cos ( )[pic 124][pic 125][pic 126]

4)        = ([pic 127] − 2) tan[pic 128][pic 129]

´ =        (        ) × tan( )[pic 130][pic 131][pic 132][pic 133][pic 134][pic 135][pic 136][pic 137]

´ =        ( [pic 138] − 2) × tan( ) + ([pic 139] − 2) ×        (tan( ))[pic 140][pic 141][pic 142][pic 143][pic 144][pic 145][pic 146][pic 147][pic 148]

´ = 3[pic 149] × tan( ) + ([pic 150] − 2) ×        (tan( ))[pic 151][pic 152][pic 153][pic 154][pic 155][pic 156]

´ = 3[pic 157] × tan( ) + ([pic 158] − 2) × sec( )²[pic 159][pic 160][pic 161]

´ =[pic 162][pic 163][pic 164][pic 165][pic 166][pic 167][pic 168][pic 169]

5)        = cot(4[pic 170])[pic 171]

´ =        (cot(4 [pic 172]))[pic 173][pic 174][pic 175][pic 176]

´ =        (cot ( )) ×        (4 [pic 177])[pic 178][pic 179][pic 180][pic 181][pic 182][pic 183][pic 184][pic 185][pic 186]

´ = − csc( )² ×        (4 [pic 187])[pic 188][pic 189][pic 190][pic 191][pic 192]

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