Generalidades
Enviado por kakaren • 16 de Agosto de 2013 • 1.191 Palabras (5 Páginas) • 245 Visitas
1. T: 24v
R1: 3.0 R4: 2300
R2:2700 R5:750
R3: 1600
RT: R1+R2+R3+R4+R5
RT: 1.608.750 Ω
I: VT = 24 = 1.491 * 10 = 0.00001491 A = I: 14.91mA
RT 1.608.750
VR1= 14.91 * 3000= 0.04473V = 44.73
VR2= 14.91 *2700= 40.25
VR3= 14.91 *160000= 23856000/ 1000000= 23.856
VR4= 14.91 *2300= 34.29
VR5= 14.91 *750= 11182.5/1000000= 11.18
VT= 24V
P= V*I
P=24 V 0.00001491 A
P= 0.00035784 W
P=357.84 m W
2. R1= 10 Ω V1=220V
R2= 15 Ω V2=220V
R3= 30 Ω V3=220V
R4= 18 Ω V4=220V
Req= 10Ω+15Ω+30Ω18Ω= 73Ω
I= VT = 220V = 3.013698
RT 73Ω
IR1= 220V = 22A
10 Ω
IR2= 220V =14.66A
15Ω
IR3= 220V =7.33A
30Ω
IR4= 220V = 12.22A
18Ω
IT= IR1+IR2+IR3+IR4 = 22A+14.66A+7.33A+12.22A= 56.21
PR1= 4.84 PR2= 3.2252 PR3=1.6126 PR4= 2.6884
RT= 1 = 0.254 = 0.255
0.01+0.666+0.033+0.055 1
3. V=?
I= 6A
R1= 3 KΩ
R2=3 KΩ 1 = 1 = 0.33 333.33Ω
R3=3 KΩ RT=
R4= 1KΩ 0.33+0.33+0.33+1+1 2.99
R5=1KΩ
V=I*R
V= 6A * 0.3333 KΩ V= 1.999Ω
I =VT = 1.999 = 6A
RT 0.333
I = V = 1.999 = 0.666 A R2, R3
R1 3000 Ω
I= V = 1.999 = 1.999 R5
R4 1000 Ω
P= I*V
1.999V*0.666A= 1331.33 Kw = 1.33306668 PR1, PR2, PR3
1.999V*1999A* 3996001Kw = 3.999 PR4, PR5
4. Rq1= R4 *R5 = 4Ω * 5Ω = 20Ω = 2.22Ω
R4 + R5 4Ω + 5Ω 9Ω
Rq2= R9 *R10 = 9Ω * 10Ω = 90Ω = 4.73Ω
R9 + R10 9Ω + 10Ω 19Ω
Rq3= R3+R4= 3Ω +6Ω=9Ω
Rq4= R7 + R8 +Rq2
Rq4= 7Ω+8Ω+4.73Ω
Rq4= 19.73Ω
Rq3= Rq4 * Rq5 = 9Ω * 19.73Ω = 177.17 = 6.18Ω
Rq4+ Rq5 9Ω + 19.73Ω 28.73
RT= R1+R2+Rq2+Rq5
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