Corriente continua
Enviado por pelao92 • 29 de Mayo de 2022 • Trabajo • 825 Palabras (4 Páginas) • 61 Visitas
CORRIENTE CONTINUA
EVALUACION N°2
[pic 1]
MALLAS
MALLA 1: -VF+R1(I1)+R2(I1-I2)+R3(I1-I2)
-24+12(I1)+10(I1)-10(I2)+8(I1)-8(I2)
-24V+12I1+10(I1-I2)+8(I1-I2)
30I1-18I2=24V
MALLA 2: R4(I2)+R6(I2-I3)+R7(I2-I3)+R3(I2-I1)+R2(I2-I1)
200 I2+420(I2-I3)+100(I2-I3)+8(I2-I1)+10(I2-I1)
738I2-520I3-18I1=0
MALLA 3: R8(I3)+R10(I3-I4)+R11(I3-I4)+R7(I3-I2)+R6(I3-I2)
190I3+600I3-600I4+310I3-310I4+100I3-100I2+420I3-420I2
1620I3-910I4-520I2=0
MALLA 4: R12(I4)+R13(I4-I5)+R11(I4-I3)+R10(I4-I3)
1000I4+2200I4-2200I5+310I4-310I3+600I4-600I3
4110I4-2200I5-910I3=0
MALLA 5: R14(I5)+R15(I5)+R13(I5-I4)
480I5+720I5+2200I5-2200I4
3400I5-2200I4=0
I1 | I2 | I3 | I4 | I5 | |
30 | -18 | 0 | 0 | 0 | 24 |
-18 | 738 | -520 | 0 | 0 | 0 |
0 | -520 | 1620 | -910 | 0 | 0 |
0 | 0 | -910 | 4110 | -2200 | 0 |
0 | 0 | 0 | -2200 | 3400 | 0 |
Se utiliza calculadora de ecuaciones Gauss-Jordan;
[pic 2]
[pic 3]
[pic 4]
[pic 5]
[pic 6]
[pic 7]
[pic 8]
I1= = 0.816A = 816mA[pic 9]
I2== 0.027A = 27mA[pic 10]
I3== 0.01A = 10mA[pic 11]
I4== 0.0037A = 3.7mA[pic 12]
I5== 0.0024A = 2.4mA[pic 13]
NODOS
NODO1:
= + [pic 14][pic 15][pic 16]
= + [pic 17][pic 18][pic 19]
- = - + [pic 20][pic 21][pic 22][pic 23][pic 24]
2 – 0.083v1 = 0.005v1 – 0.005v2 + 0.055v1
2 = 0.083v1 + 0.005v1 + 0.055v1 – 0.005v2
2 = 0.0143v1 – 0.005v2
NODO 2:
= + [pic 25][pic 26][pic 27]
= + [pic 28][pic 29][pic 30]
- = - + [pic 31][pic 32][pic 33][pic 34][pic 35]
...