ISOTERMAS DE ADSORCION

Haga una gráfica de la cantidad adsorbida en función de la concentración de las soluciones de ácido acético y compruebe si cumple con la ecuación de Henry. Calcule la constante k.

NaOH+ 〖CH〗_3 COOH 〖CH〗_3 COONa + H_2 O

Solución

Calculo de moles de 〖CH〗_3 COOH iniciales

Calculo de moles de 〖CH〗_3 COOH finales

Calculo de no. De moles de 〖CH〗_3 COOH por cada gramo de carbón activado.

(X/g)

B C_(〖CH〗_3 COOH INCIAL )=(5ml )(1M)/((250ml) )=0.02 M〖CH〗_3 COOH

((0.02 mol )/(1 l))(0.005 l〖CH〗_3 COOH)

= 0.0004 mol 〖CH〗_3 COOH C_(〖CH〗_3 COOH FINAL)=((0.1M)(1.1 ml))/((5 ml) )=0.02 M

((0.02 mol)/(1 l ))(0.025l )=0.0005 mol 〖CH〗_3 COOH

0.0004 mol-0.0005 mol= -0.0001 mol 〖CH〗_3 COOH

((-0.0001〖CH〗_3 COOH)/(1 g de Carbon activado))=

-0.0001 mol 〖CH〗_3 COOH/ g Car. Activado.

C C_(〖CH〗_3 COOH INCIAL )=(5ml )(1M)/((100ml) )=0.05 M〖CH〗_3 COOH

((0.05 mol )/(1 l))(0.005 l〖CH〗_3 COOH)

= 0.00025 mol 〖CH〗_3 COOH C_(〖CH〗_3 COOH FINAL)=((0.1M)(1.6 ml))/((5 ml) )=0.032 M

((0.032 mol)/(1 l ))(0.025l )=0.0008 mol 〖CH〗_3 COOH

0.00025 mol-0.0008 mol= -0.0005 mol 〖CH〗_3 COOH

((-0.0005〖CH〗_3 COOH)/(1 g de Carbon activado))=

-0.0005 mol 〖CH〗_3 COOH/ g Car. Activado.

D C_(〖CH〗_3 COOH INCIAL )=(10ml )(1M)/((100ml) )=0.1 M〖CH〗_3 COOH

((0.1 mol )/(1 l))(0.01 l〖CH〗_3 COOH)

= 0.001 mol 〖CH〗_3 COOH C_(〖CH〗_3 COOH FINAL)=((0.1M)(3.5 ml))/((5 ml) )=0.07 M

((0.07 mol)/(1 l ))(0.025l )=0.00175 mol 〖CH〗_3 COOH

0.001 mol-0.00175 mol= -0.0007mol 〖CH〗_3 COOH

((-0.0007〖CH〗_3 COOH)/(1 g de Carbon activado))=

-0.0007 mol 〖CH〗_3 COOH/ g Car. Activado.

E C_(〖CH〗_3 COOH INCIAL )=(20ml )(1M)/((100ml) )=0.2 M〖CH〗_3 COOH

((0.2 mol )/(1 l))(0.02 l〖CH〗_3 COOH)

= 0.004 mol 〖CH〗_3 COOH C_(〖CH〗_3 COOH FINAL)=((0.1M)(7.6 ml))/((5 ml) )=0.152 M

((0.152 mol)/(1 l ))(0.025l )=0.00312 mol 〖CH〗_3 COOH

0.004 mol-0.00312 mol= 0.00088mol 〖CH〗_3 COOH

((0.00088〖CH〗_3 COOH)/(1 g de Carbon activado))=

0.00088 mol 〖CH〗_3 COOH/ g Car. Activado.

F C_(〖CH〗_3 COOH INCIAL )=(25ml )(1M)/((100ml) )=0.25 M〖CH〗_3 COOH

((0.25 mol )/(1 l))(0.025 l〖CH〗_3 COOH)

= 0.00625 mol 〖CH〗_3 COOH C_(〖CH〗_3 COOH FINAL)=((0.1M)(10.15 ml))/((5 ml) )=0.203 M

((0.203 mol)/(1 l ))(0.025l )=0.00507 mol 〖CH〗_3 COOH

0.00625 mol-0.00507 mol= 0.00118mol 〖CH〗_3 COOH

((0.00118〖CH〗_3 COOH)/(1

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