Resolución De Identidades Notables

Identitats notables

Recorda (espero que les memoritzeu):

1. Desenvolupar utilitzant les identitats notables:

a) = x²-2x+1

= (x-1) (x-1) = x²-x-x+1

b) = x²+2x+1

= (x+1) (x+1) = x²+x+x+1

c) = x²-1

= x²-x+x-1 = x²-1

d) = x²-4x+4

= (x-2) (x-2) = x²-2x-2x+4 = x²-4x+4

e) = 4x²-4x+1

= (2x-1) (2x-1) = 4x²-2x-2x+1 = 4x²-4x+1

f) = 4x²-12x+9

= (2x-3) (2x-3) = 4x²-6x-6x+9 = 4x²-12x+9

g) = x²-4

x²+2x-2x-4 = x²-4

h) = x²-4x+4

= (-x+2) (-x+2) = x²-2x-2x+4 = x²-4x+4

i) = x2-4x+4

= (2-x) (2-x) = 4-2x-2x+x2 = x2-4x+4

j) = 9x2+12x+4

= (2+3x) (2+3x) = 4+6x+6x+9x2 = 9x2+12x+4

k) = 4x2-1

4x2-2x+2x-1 = 4x-1

l) = x4-x2+1

= (x2-1) (x2-1) = x4-x2-x2+1 = x4-2x2+1

m) = x4+2x3+x2

= (x2+x) (x2+x) = x4+x3+x3+x2 = x4+2x3+x2

n) = x²+2x+1

= (-x-1) (-x-1) = x²+x+x+1 = x²+2x+1

o) = x4-1

= x4-x2+x2-1 = x4-1

p) = 4x4-12x3+9x2

= (2x2-3x) (2x2-3x) = 4x4-6x3-6x3+9x2 = 4x4-12x3+9x2

q) = x²-2x+1

= (x-1) (x-1) = x²-x-x+1 = x2-2x+1

r) = -4x2+9

= 9+6x-6x-4x2 = 9-4x2

s) = +4x²+12x+9

= (-2x-3) (-2x-3) = +4x²+6x+6x+9 = +4x²+12x+9

t) = x²-2x+1

= (-x+1) (-x+1) = x²-x-x+1 = x²-2x+1

u) = x2-9

= x2+3x-3x-9 = x2-9

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