Tarea de investigación: MAXIMIZAR: 1 X1 + 3 X2 + 2 X3
Elperro ElgatoTarea22 de Octubre de 2015
765 Palabras (4 Páginas)376 Visitas
Presentado por: Israel Antonio Castiblanco C.                                         Código: 31555
MAXIMIZAR: 1 X1 + 3 X2 + 2 X3  | [pic 1]  | MAXIMIZAR: 1 X1 + 3 X2 + 2 X3 + 0 X4 + 0 X5 + 0 X6  | ||||||
3 X1 + 1 X2 + 2 X3 ≤ 7  | 3 X1 + 1 X2 + 2 X3 + 1 X4 = 7  | |||||||
X1, X2, X3 ≥ 0  | X1, X2, X3, X4, X5, X6 ≥ 0  | |||||||
Tabla 1  | ||||||||
Base  | z  | b  | X1  | X2  | X3  | X4  | X5  | X6  | 
X4  | 0  | 7  | 3  | 1  | 2  | 1  | 0  | 0  | 
X5  | 0  | 6  | 1  | 2  | 0  | 0  | 1  | 0  | 
X6  | 0  | 40  | 4  | 3  | 8  | 0  | 0  | 1  | 
Z  | 
  | 0  | -1  | -3  | -2  | 0  | 0  | 0  | 
Tabla 2  | ||||||||
Base  | z  | b  | X1  | X2  | X3  | X4  | X5  | X6  | 
X4  | 0  | 4  | 2.5  | 0  | 2  | 1  | -0.5  | 0  | 
X2  | 3  | 3  | 0.5  | 1  | 0  | 0  | 0.5  | 0  | 
X6  | 0  | 31  | 2.5  | 0  | 8  | 0  | -1.5  | 1  | 
Z  | 
  | 9  | 0.5  | 0  | -2  | 0  | 1.5  | 0  | 
Tabla 3  | ||||||||
Base  | z  | b  | X1  | X2  | X3  | X4  | X5  | X6  | 
X3  | 2  | 2  | 1.25  | 0  | 1  | 0.5  | -0.25  | 0  | 
X2  | 3  | 3  | 0.5  | 1  | 0  | 0  | 0.5  | 0  | 
X6  | 0  | 15  | -7.5  | 0  | 0  | -4  | 0.5  | 1  | 
Z  | 
  | 13  | 3  | 0  | 0  | 1  | 1  | 0  | 
La solución óptima es Z = 13
2) El vector de disponibilidad cambia a 4, 5,6 
MAXIMIZAR: 1 X1 + 3 X2 + 2 X3  | [pic 2]  | MAXIMIZAR: 1 X1 + 3 X2 + 2 X3 + 0 X4 + 0 X5 + 0 X6  | 
3 X1 + 1 X2 + 2 X3 ≤ 4  | 3 X1 + 1 X2 + 2 X3 + 1 X4 = 4  | |
X1, X2, X3 ≥ 0  | X1, X2, X3, X4, X5, X6 ≥ 0  | 
Tabla 3  | ||||||||
Base  | Z  | b  | X1  | X2  | X3  | X4  | X5  | X6  | 
X4  | 0  | 7 / 8  | 15 / 8  | 0  | 0  | 1  | -1 / 8  | -1 / 4  | 
X2  | 3  | 5 / 2  | 1 / 2  | 1  | 0  | 0  | 1 / 2  | 0  | 
X3  | 2  | 5 / 16  | 5 / 16  | 0  | 1  | 0  | -3 / 16  | 1 / 8  | 
Z  | 
  | 65 / 8  | 9 / 8  | 0  | 0  | 0  | 9 / 8  | 1 / 4  | 
La solución óptima se ha modificado bastante
Se cambia el vector X3 por 2, 3,4
Tabla 2  | ||||||||
Base  | Z  | b  | X1  | X2  | X3  | X4  | X5  | X6  | 
X4  | 0  | 4  | 2.5  | 0  | 0.5  | 1  | -0.5  | 0  | 
X2  | 3  | 3  | 0.5  | 1  | 1.5  | 0  | 0.5  | 0  | 
X6  | 0  | 1  | 2.5  | 0  | -0.5  | 0  | -1.5  | 1  | 
Z  | 
  | 9  | 0.5  | 0  | 2.5  | 0  | 1.5  | 0  | 
Se insertan X7 X8 con 2,5,1 4,1,7
MAXIMIZAR: 1 X1 + 3 X2 + 2 X3 + 8 X4 + 15 X5  | [pic 3]  | MAXIMIZAR: 1 X1 + 3 X2 + 2 X3 + 8 X4 + 15 X5 + 0 X6 + 0 X7 + 0 X8  | 
3 X1 + 1 X2 + 2 X3 + 2 X4 + 4 X5 ≤ 7  | 3 X1 + 1 X2 + 2 X3 + 2 X4 + 4 X5 + 1 X6 = 7  | |
X1, X2, X3, X4, X5 ≥ 0  | X1, X2, X3, X4, X5, X6, X7, X8 ≥ 0  | 
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