ALGEBRA
Enviado por jkhkj154151 • 27 de Octubre de 2021 • Tarea • 1.086 Palabras (5 Páginas) • 58 Visitas
- [pic 1][pic 2][pic 3][pic 4][pic 5][pic 6][pic 7][pic 8][pic 9][pic 10][pic 11][pic 12][pic 13][pic 14][pic 15][pic 16][pic 17][pic 18][pic 19][pic 20][pic 21][pic 22][pic 23][pic 24][pic 25][pic 26][pic 27][pic 28][pic 29]
[pic 30]
[pic 31]
- P=1/2 ( a+b+c ) P=1/2 (150.00 + 212.93+14301)[pic 32]
II.
P= ½ (323.93+125+212.84)[pic 33]
P=275.385 / 2 =
P – a = 12.6925
P – b = 75.2375
P – c = 75.1475
[pic 34]
Tan ½ A = √ (75.2375) (75.1475) = Tan ½ A = 1.79864609 =
(137.6925 (12.6925)
A = 121° 51´15.05”
Tan ½ A = √ (P – b) (P – c)
P(P – a)[pic 35]
P – a = 102.97
P – b = 40.04
P – c = 109.96
Tan ½ A = √ (40.04) (109.96) = Tan ½ A = 0.4111256122 =
252.97 (102.97)[pic 36]
A = 44°45´51.5”
[pic 37]
Tan ½ B = √ (102.97) (109.96) = tan ½ B = 1.057282825
252.97 (40.04)
B = 93°11´23.48”
[pic 38]
Tan ½ C = √ (102.97) (40.04) = tan ½ C = 0.3849909448
252.97 (109.96)
C= 42°6´45.03”[pic 39]
S = √ 252.97 (102.97) (40.04) (109.96)
S = 10709.13188
[pic 40]
Tan ½ B = √ (12.6925) (75.1475) = tan ½ B = 0.3034300117
(137.6925) ( 75.2375)
B = 33°45´31.48”
Tan ½ C = √(12.6925) (75.2375) = tan ½ C = 0.303793413
(137.6925)(75.1475)[pic 41]
C = 33°47´48.74”[pic 42]
S = √ 137.6925 (75.2375) (75.1475) (12.6925)
S = 3143.425525
Tan ½ B = √ (142.228882) (44.48370623) = tan ½ B = 1.431125586
(168.3562938) (18.35.62938)[pic 43]
B = 110°6´43.55”
Tan ½ C = √ (142.228882) (18.3562938) = tan ½ C = 0.5905569467
(168.3562938) (44.48370623)[pic 44]
C = 61°7´42.74”
P = ½ ( a+b+c)
P = ½ (212.84 + 190.00 + 310.5851751)
P = 336.7125876 / 2
P = 168.3562938[pic 45]
P – a = 142.2288813
P – b = 18.3562938
P – c = 44.48370623
Tan ½ A = √ (18.3562938) (44.48370623) = tan ½ A = 0.1846649219
(168.3562938) (142.2288813)[pic 46]
...