ECUACIONES DE EQULIBRIO

República Bolivariana de Venezuela[pic 1]

Ministerio del Poder Popular para la Defensa

Universidad Nacional Experimental de la Fuerza Armada Nacional Bolivariana UNEFA

Cátedra: Teoría de Estructura I

Carrera: Ingeniería Civil

ASIGNACION N°2

ECUACIONES DE EQULIBRIO

Profesor: Jesús Rafael Zurita Méndez

Estudiante:

Araminta Braque V.  

Cedula:

V- 16.820.039

Guatire, Agosto 2021

EJERCICIOS: ANALIZAR LAS SIGUIENTES ESTRUCTURAS

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Formula:

GHT=NR-NEE-C

GL= 3NN-NR

NR = 2 + 2 + 2 = 6

NEE = 3

NN = 3

C = 0

NE = 3

GHE = NR – NEE

GHE = 6 – 3 = 3

GHE = 3

2D                                                          

GHI = NE – 3NN + 3

GHI = 3 – 3(2) + 3 = 0

GHI = 0

GL = 3NN – NR

GL = 3(2) – 6 = 0

GL = 0

GHT=NR-NEE-C

GHT = 6 – 3 - 0 = 3

GHT = 3

3D

GHI = NE – 3NN + 6

GHI = 3 – 3(2) + 6 = 3

GHI = 3

GL = 3NN – NR

GL = 3(2) – 6

GL = 0

GHT=NR-NEE-C

GHT = 3

Estructura Isostática

(2D) GHT = 3  0[pic 50]

(3D) GHT = 3  0[pic 51]

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Formula:

NR = 3 + 2 = 5

NEE = 3

NN = 2

C = 2

NE = 3

GHE = NR – NEE – C

GHE = 5 - 3 – 2 = 0

GHE = 0

2D

GHI = 3NE – 3NN -NR

GHI = 3(3) – 3(2) - 5

GHI = -2

GL = 3NN – NR

GL = 3(2) – 5 = 1

GL = 1

GHT = GHE + GHI

GHT = 0 + (-2)

 GHT = -2

3D

GHI = 6NE – 6NN + NEE

GHI = 6(3) – 6(2) + 3

GHI = 9

GL = 6NN – NR

GL = 6(2) – 5 = 7

GL = 7

GHT = GHE + GHI

GHT = 0 + 9 = 9

Estructura Isostática

(2D) GHT = -2  0[pic 92]

(3D) GHT = 9  0[pic 93]

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Formula:

NR = 2 + 2 = 4

NEE = 3

NN = 2

C = 0

NE = 5

GHE = NR – NEE

GHE = 4 – 3 = 1

GHE = 1

2D

GHI = NE – 2NN + 3

GHI = 5 – 2(2) + 3 = 4

GHI = 4

GL = 2NN – NR

GL = 2(2) – 4 = 0

GL = 0

GHT = 1 + 4 = 5

GHT = 5

3D

GHI = NE – 3NN + 6

GHI = 5 – 3(2) + 6

GHI = 5

GL = 3NN – NR

GL = 3(2) – 4

GL = 2

GHT = GHE + GHI

GHT = 1 + 5 = 6

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