Estadistica Media Aritmetica Por Los Tres Metodo
miyagi30 de Noviembre de 2012
720 Palabras (3 Páginas)8.472 Visitas
MEDIDAS DE TENDENCIA CENTRAL INT. DE CLASE FC MC FC.MC D=MC.A FC.D V=D/C FC.U
30-39
40-49
50-59
60-69
70-79
80-89
90-99
18
64
86
42
22
6
2 34.5
44.5
53.5
64.5
74.5
84.5
94.5 621
2,848
4,687
2,709
1,639
507
189
-30
-20
-10
0
10
20
30 -540
-1,280
-860
0
220
120
60
-3
-2
-1
0
1
2
3 -54
-128
-86
0
22
12
6
MEDIDAS DE TENDENCIA CENTRAL
MEDIA ARITMETICA POR METODO LARGO.
X ̅=(∑▒〖FC.MC〗)/N =13,200/240 = 55
METODO CORTO O CLAVE.
X ̅= A+(∑▒〖FC.D〗)/N = 64.5 + (- 2,280/240 )=
D=MC.A
A=64.5 =64.5-9.5=55
METODO DE COMPILACION.
X ̅= A +((∑▒〖FC.U〗)/N) C
A= 64.5 64.5+((- 228 )/240) 10 =-2,280/240 = - 9.5
U= D/C = 64.5 – 9.5 = 55
MEDIANA.
Me= Lri +[(n/2-∑▒fant)/(f med)] c
N/2 = 240 = 120
Me= 49.5+ ((120-82)/86) 10
Me= 49.5 +(38/86) 10
Fmed= 86
∑▒〖fant=〗 82
Lri=49.5
C= 10 Me=49.5+ (380/86) =4.41
Me =49.5 + 4.41 = 53.91
MODA.
Mo. = Lri (∆1/(∆1+ ∆2) ) c Mo= 49.5 + (22/(22+44)) 10
Mo = 49.5+ (220/66) = 3.33
C= 10
Fmodal= 86
Lri= 49.5
Mo= 49.5 + 3.33 = 52.83
INT.DE CLASE FC MC
30-39
40-49
50-59
60-69
70-79
80-89
90-99
18
64
86
42
22
6
2 34.5
44.5
54.5
64.5
74.5
84.5
94.5
∑▒〖=240〗
CALCULAR. 1. - Q1 Y Q3
2. - D1 Y D6
3.-P35 Y P90
I=1 Q4= Lri + (((i.N∑▒fant)/i)/fq) c
Fq=64
Lri=39.5
Fant=18 1,240/4 = 240/4 = 60
C= 10
Q1= 39.5 +((60-18)/64) 10
Q1=39.5 + (42/64) 10= 420/64 = 6.56
Q1 = 39.5 + 6.56 = 46.06
I = 3 Q1 = Lri + (((i .N)/4-∑▒fant)/fq) c
Fq= 42
Lri= 59.5
Fant = 168
C = 10
3,240/4 = 720/4 = 180
Q3= 59.5 + (180-168)/42 = 10 = (12/42)10
Q3=59.5 + (120/42) = 2.85
Q3= 59.5 +2.85 = 62-35
Di= Lri + (((i.N)/10-∑▒fant)/fd)c
Int. De clase FC MC
FC.MC
30 39 18 34.5 621 -20.5 -369
420.25
7564.5
40 49 64 44.5 2848 -10.5 -672 110.25 7056
50 59 86 54.5 4687 -0.5 -43 0.25 21.5
60 69 42 64.5 2709 9.5 399 90.25 3790.5
70 79 22 74.5 1639 19.5
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