Ead Geometria

UNIDAD 1

Actividad A5

La Presa

Con las coordenadas de cada punto calcula los perímetros y áreas de las 4 partes que forman la presa, también responde las preguntas solicitadas.

Cálculo de Perímetros

Enrocamiento A1

ENROCAMIENTO: A(0,0), B(10,0), C(16,30)

AB =√(〖(0)〗^2+〖(0)〗^2 ) = √(〖(10)〗^2+〖(0)〗^2 ) = √100 = 10

BC = √(〖(10)〗^2+(16 )^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √936 = 30.59

CA = √(〖(16)〗^2+〖(0)〗^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √1156 = 34

PERIMETRO: = 74.59 m

Corazón A2

CORAZON: A(16, -4), B(20, -4), C(24,0), D(26,0), E(19,30), F(16,30), G(10,0), H(13,0)

AB = √(〖(16) 〗^2+〖(20)〗^2 ) = √(〖(-4)〗^2+〖(-4)〗^2 ) = √16 = 4

BC = √(〖(20)〗^2+〖(24)〗^2 ) = √((-4)^2+〖(0)〗^2 ) = √32 = 5.6

CD = √(〖(24)〗^2+〖(26)〗^2 ) =√(〖(0)〗^2+〖(0)〗^2 ) =√4 = 2

DE = √(〖(26)〗^2+〖(19)〗^2 ) =√(〖(0)〗^2+〖(30)〗^2 ) = √949 = 30.8

EF = √(〖(19)〗^2+〖(16)〗^2 ) =√((〖30)〗^2+〖(30)〗^2 ) =√9 = 3

FG = √(〖(16)〗^2+〖(10)〗^2 ) = √(〖(30)〗^2+〖(0)〗^2 ) = √936 = 30.59

GH = √(〖(10)〗^2+〖(13)〗^2 ) = √(〖(0)〗^2+〖(0)〗^2 ) =√9 = 3

HA =√(〖(13)〗^2+〖(16)〗^2 ) = √(〖(0)〗^2+〖(-4)〗^2 ) = √25= 5

PERIMETRO = 83.99 m

Filtro A3

FILTRO: A(26,0), B(27,0), C(20,30), D(19,30)

AB = √(〖(26)〗^2+〖(27)〗^2 ) =√(〖(0)〗^2+〖(0)〗^2 ) = √1 = 1

BC = √(〖(27)〗^2+〖(20)〗^2 ) = √(〖(0)〗^2+〖(30)〗^2 ) = √949 = 30.80

CD = √(〖(20)〗^2+〖(19)〗^2 ) =√(〖(30)〗^2+〖(30)〗^2 ) =√1 = 1

DA = √(〖(19)〗^2+〖(26)〗^2 ) =√(〖(30)〗^2+〖(0)〗^2 ) = √949 = 30.80

PERIMETRO = 63.6 m

Enrocamiento A4

ENROCAMIENTO: A(27,0), B(37, 0), C(20,30)

AB= √(〖(27)〗^2+〖(37)〗^2 ) = √(〖(0)〗^2+〖(0)〗^2 ) = √100 = 10

BC = √(〖(37)〗^2+〖(20)〗^2 ) =√(〖(0)〗^2+〖(30)〗^2 ) √1189 = 34.48

CA = √(〖(20)〗^2+〖(27)〗^2 ) √(〖(30)〗^2+〖(0)〗^2 ) = √949 = 30.80

PERIMETRO: 75.28 m

Cálculo de Áreas:

Enrocamiento A1

ENROCAMIENTO: A(0,0), B(10,0), C(16,30)

0 0

10 0

16 30

0 0

A= 1/2

Area = 150 m2

Corazón A2

CORAZON: A(16, -4), B(20, -4), C(24,0), D(26,0), E(19,30), F(16,30),

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