Operaciones básicas en algebra
Enviado por hernancvzT • 18 de Noviembre de 2021 • Examen • 3.719 Palabras (15 Páginas) • 77 Visitas
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Operaciones básicas en algebra
Suma
1.- 3x – 5x2 + 8x4 + x + 2x2 -13x3 + 3
3x – 5x2 – 8x4
X + 2x2 -13x3 +3[pic 7]
4x -3x2- 8x4- 13x3 + 3 R: 4x -3x2- 8x4- 13x3 + 3
2.- 2ab – 3ª2b – 7ª2b – 8ab
2ab – 3ª2b
-8ab -7ª2b[pic 8]
-10ab – 10ª2b R: -10ab – 10ª2b
3.-3x4 + -8x4 + 2x2 + -7x4 + -11x2
3x4 2x2
-8x4 -11x2
-7x4[pic 9]
-12x4 – 9x2 R: -12x4 – 9x2
4.- 5x2 + 3x + 2x
5x2 + 3x
+2x [pic 10]
5x2 + 5x R: 5X2 + 5X
5.- 3x – 8y – 2z + 7x + 3y + z
3x – 8y – 2z
7x + 3y + z[pic 11]
10 x – 5y – z R: 10x – 5y – z
Resta
Multiplicación
División
Simplificación de expresiones racionales
Multiplicación
1.- x2 + 2x – 3 x 3x + 12 = (x +3) (x-1) X 3( x+4) = (x + 3) X 3 = 3( x + 3)[pic 12][pic 13][pic 14][pic 15][pic 16][pic 17][pic 18][pic 19][pic 20][pic 21]
X2 + 8x +16 x – 1 (x + 4) (x + 4) x – 1 (x+ 4) 1 (x + 4)[pic 22]
2.- x2 + 2x – 15 X x- 5 = (x+ 5) (x-3) X x – 5 = ( x- 3) X 1 = X – 3 [pic 23][pic 24][pic 25][pic 26][pic 27][pic 28][pic 29][pic 30][pic 31]
X2 – 25 x – 2 (x-5) (x+ 5) x + 2 1 X + 2 X + 2[pic 32][pic 33]
3.- t – 3 X t + 3 = t2 – 9 = 1[pic 34][pic 35][pic 36][pic 37]
T2 + 9 t2 - 9 ( t2 + 9) (t2 – 9) t2 + 9
4.- x – 3 X x+ 5 = - (x- 3 ) x x + 5 = -1 X 1 = -1 [pic 38][pic 39][pic 40][pic 41][pic 42][pic 43][pic 44]
4x + 20 x2 – 9 4 ( x + 5) (x – 3) ( x + 3) 4 4 (x – 3) 4x - 12
5.- x + 2 X x + 4 = x + 2 = x + 4 = 1 X 1 = 1 [pic 45][pic 46][pic 47][pic 48][pic 49][pic 50][pic 51]
3x + 12 x2 - 4 3 (x + 4) (x – 2) (x + 2) 3 x – 2 3 x - 6
División
- 2y3-10y2-48y ÷ y2+5y+6 = 2y(y2-5y-24) x 9y4+18y3 = 2y(y2+3y-8y-24) x 3(3y4+6y3)
3y-24 9y4+18y3 3(y-8) y2+5y+6 3(y-8) y2+3y+2y+6
= 2y(y(y+3)-8(y+3)) x 3y3(y+2) = 2y(y+3) (y-8) x 3y3(y+2) = 2y x 3y3 = 6y4
3(y-8) y(y+3) +2(y+3) y-8 (y+3) (y+2)
- -20 ÷ 4 = - 20 x 15y3 = -5 x 5 = 25[pic 52]
9y3 15y3 9y3 4 3 3
- -8b4 ÷ -4 = -8b4 x 3b2 = 2b4 x b2 = 2b6
3 3b2 3 4
- 5b2 ÷ -10 = 5b2 x 2b3 = -b2 x b3 = b5[pic 53]
2 2b3 2 10 2 2
- 3y2 ÷ 2 = y2 x 7y4 = 7y6
6 7y4 2 2 4
Teorema de Pitágoras
1.- Calcula el lado que falta
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