Ejercicios De Calculo Integral
Enviado por logan212 • 10 de Noviembre de 2014 • 870 Palabras (4 Páginas) • 314 Visitas
8) F(x)=3x^2-x+10 b=x=10 a=x=0
dw= ∫_a^b▒F(x)dx
dw= ∫_0^10▒〖(3x^2 〗-x+10) dxp?
dw=3∫_0^10▒〖x^2 dx-∫_0^10▒〖x dx+10∫_0^10▒dx〗〗
w=[(3x^3)/3 - x^2/2+10x] ∫_0^10
w= [x^3-x^2/2+10x] ∫_0^10
w=[〖10〗^3-〖10〗^2/2+10 (10)]-[0^3-0^2/2+10(0)]
w = 1050 unidades de trabajo
9) DCX)= cx+10)^(2 ) p=$10000
p=(x+10)^2
10000=(x+10)^2
x+10=√10000
x+10=100
x=100-10
x=90
EC=∫_0^90▒〖(x+10)^2 〗 dx - 90 (10000)
Ec=∫_0^90▒〖(x+10)^2 dx-900000〗
Ec=∫_0^90▒〖(x^2+20x+100)dx-900000〗
Ec=∫_0^90▒〖x^2 dx+20 ∫_0^90▒〖x dx+100∫_0^90▒〖dx-900000〗〗〗
Ec=[x^3/3+ (20x^2)/2+100x] ∫_0^90▒〖- 900000〗
Ec= ((90)^3)/3+10(90)^2+100(90)-900000
Ec=333000-900000
Ec=$ 576000
10) Dc x)=1000-0,4x^2
Sc x)=42x
Ec=∫_0^x▒〖Dcx) dx -xp〗
Ep=xp-∫_0^x▒s(x)dx
Dcx=0,4x^2
1000-0,4x^2
Scx=42x
0,4x^2+42x-1000=0
(x=105±√((105)^2-4(1)(-2500)))/(2(1))
x=(-105±145)/2
x=40/2
x=20
s(20)=42 (20) D(20)=1000-0,4(20)^2
s (20)=840 D(20)=840
p=S (20)=D(20)
p=$840
EC=∫_0^20▒〖(1000-0,4x^2 ) dx-840 (20) 〗
EC=1000∫_0^20▒〖dx-0,4∫_0^20▒〖x^2 dx -16800 〗〗
EC=[1000x-(0,4x^3)/3] ∫_0^20 16800
EC=[1000(20) (.0,4 (20)^3)/3]-16800
EC=19992-16800
EC=3192
EP=20 (840)-∫_0^20▒〖42 x dx〗
EP=16800-42∫_0^20▒〖x dx〗
EP=16800- [(42x^2)/2] ∫_0^20
EP=16800- [21x^2 ] ∫_0^20
EP=16800-[21(20)^2-21(0)^2 ]
EP=16800-8400
EP=8400
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