GEOMETRIA ANALITICA
Enviado por jxft.241 • 29 de Agosto de 2014 • 1.225 Palabras (5 Páginas) • 375 Visitas
Tabla resumen
Número Sección Perímetro (m) Área (m2)
1 Enrocamiento 93.48 200 u2
2 Corazón 100 902.5 u2
3 Filtro 89.6 40 u2
4 Enrocamiento 99.08 180 u2
Enrocamiento
AB=10
BC= B (xb, yb) y C (xc, yc)
Es decir
Xb= 10 xc= 16
Yb= 0 yc= 40
Sustituir en la formula
(BC)2 = (BC)2 X + (BC)2 Y
(BC)2= + (yc-yb)2
(BC)2 =
(BC)2= = √1636
BC= 40.4
(CA)=?
C=(16,40)
A= (0,0)
C= (Xc,Yc) y A (Xa,Ya)
Es decir
Xa = 0 ; Xc = 16
Ya = 0 ; Yc = 40
CA = (CA)x2 + (CA) y2
CA =
CA =
CA =
Perímetro:
AB + BC + CA= 10 + 40.4 + 43.08 =93.48 m
Corazón
DB
B (10,0)
D (13,0)
Dx = 13
Bx = 10
Dy = 0
By = 0
PB = (Dx - Bx) – (Dy - By)
DB = (13 - 10) – (0 - 0)
DB = (3 - 0) = 3
DB =3
ED
E (16, - 5)
D (13 ,0)
Ex = 16
Dx = 13
Ey = -5
Dy = 0
ED = (Ex –Dx ) – ( Ey - Dy)
ED = ( 16 - 13) – ( -5 – (- 5)
ED = (3) – (-5 )
ED = 8
FE
F (20, -5)
E (16, -5)
Fx = 20
Ex = 16
Fy = -5
Ey = -5
FE = (Fx - Ex) – (Fy – Ey)
FE = (20 - 16) – (- 5 – (-5)
FE = 4 – (0)
FE = 4
GF
G = (24,0)
F = (20, - 5)
Gx = 24
Fx = 20
Gy = 0
Fy = -5 GF = (6x – Fx ) – ( Gy – Fy)
GF = (24 -20) – (0-(-5)
GF = 4 – (5) = -1
HJ = H (XH, YH) ; H( 26, 0)
Y J (XJ, YJ) ; (19,40)
XH= 26 XJ= 19
YH= 0 YJ= 40
SUSTITUIR EN FORMULA
(HJ)2= (HJ)2X + (HJ)2 Y
(HJ)2=
(HJ)2=
(HJ)2= =
= 40.60 m
JC
J(19.40)
C=(16,40
J( XJ, YJ) Y C ( XC, YC)
ES DECIR
XJ= 19 XC= 16
YJ= 40 YC= 40 SUSTITUIR EN FORMULA
(JC)2=
(JC)2 =
(JC)2 =
(JC)2 =
= 3
Perímetro Corazón
DB + ED + FE + GF + HG + JH + JC + BC
3 + 8 + 4 + (-1) + 2 + 40.60 + 3 + 40.4 = 100 m
Distancia Filtro
IH =
H= (26, 0)
I = (27, 0)
Hx = 26
Ix = 27
Hy = 0
Iy = 0
HI = ( Ix - Hx) – ( Iy - Hy)
HI = (27 – 26 ) – (0 – 0 )
HI = ( 1 – 0 ) = 1
KI =
K= ( 20, 40)
I = ( 27, 0 )
Kx = 20
Ky = 40
Ix = 27
Iy = 0
KI =(Ix - Kx) – ( Iy – Ky )
KI = ( 27 – 20 ) – (0 – 40 )
KI = 7 – (-40 ) = 47
KJ=
K = ( 20, 40 )
J = ( 19, 40 )
Kx = 20
Ky = 40
Jx = 19
Jy = 40 KJ = ( Kx – Jx ) – ( Jy - Ky)
KJ = ( 20 – 19 ) – ( 40 - 40)
KJ = ( 1) – ( O ) = 1
Perímetro Filtro
HI + IK + KJ + JH = 1+ 47 + 1 + 40.60 = 89.6 m
Enrocamiento
IA =
I ( 27, 0)
A ( 36, 0)
Ax = 36
Ay = 0
Ix = 27
Iy = 0
IA = ( Ax – Ix ) – ( Ay - Iy)
...