METODO FRACCIONES PARCIALES - UNH - Castañeda
Enviado por Javier Rivera Vargas • 3 de Diciembre de 2018 • Síntesis • 1.758 Palabras (8 Páginas) • 158 Visitas
MÉTODO DE FRACCIONES PARCIALES
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Es una fracción propia.
Solución.
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ENTONCES.
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FORMANDO SISTEMA DE ECUACIONES.
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EN 1
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En 2 remplazando 1
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REMPLAZANDO EN 1
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REMPLAZANDO EN LA INTEGRAL.
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Solución
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Solución:
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Resolviendo:
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Igualando los coeficientes para sacar las ecuaciones
- → (3A+B+C = 0) 4 → 12A+4B+4C=0 ↓(-)[pic 73]
- → (4B+2C=1)2 → 8B+4C=2[pic 74]
- → 4B+4C=5 → 4A 4B+4C=5 ↑(-)[pic 75][pic 76][pic 77]
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Resolviendo la integral
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- Factorizamos:
1 | -2 | -25 | 26 | 120 | |
+3 | 3 | 3 | -66 | -120 | |
1 | 1 | --22 | 40 | 0 | |
5 | 5 | 30 | 40 | ||
1 | 6 | 8 | 0 | ||
-2 | -2 | -8 | |||
1 | 4 | 0 |
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e) Resolver:
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Resolución:
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Factorizando el denominador:
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Por tanto nos queda:
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Dividiendo el numerador entre el denominador:[pic 119]
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Entonces:
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Hallando “I”
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Formando sistema de ecuaciones:
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f) Resolver:
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Resolución:
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Por lo tanto:
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F[pic 146][pic 147]
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Formando sistema de ecuaciones:
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Solución
; Grado: 5[pic 161]
; Grado: 7 [pic 162][pic 163][pic 164]
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+F () +G [pic 169][pic 170][pic 171][pic 172]
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Igualando los coeficientes:
- B+G=0
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Resolviendo la integral:
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solución:
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SISTEMA DE ECUACIONES:
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Solución
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j)
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