Teoria de conjuntos
Enviado por TheLoCo2013 • 9 de Mayo de 2021 • Ensayo • 1.437 Palabras (6 Páginas) • 63 Visitas
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TEORIA DE CONJUNTOS
Profesor: Integrantes:
Betzimar Puerta Gabriela Verde
30.363.286
El Tigre, mayo 2021
Dados los siguientes conjuntos, determine que conjuntos se forman según su simbología. 2
Si U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14 15 }
A = { 4, 8, 10, 12 } B = { 3, 6, 9, 12, 15 }
C = { 1, 2, 3, 11, 12, 13 } D = { 1, 5, 6, 10, 11 }
E = {12, 13, 14, 15}
a) A ∪ B={4,8,10,12,3,6,9,15}
b) (A ∩ B)c = {12}
(A ∩ B) = {12}
(A ∩ B)c = {1,2,3,4,5,6,7,8,9,10,11,13,14,15}
(A ∩ B)c= {1,2,3,4,5,6,7,8,9,10,11,13,14,15}
c) (D ∩ E) – A
D ∩ E)= {ø}
(D ∩ E)= {ø} – A={ø}
(D ∩ E)–A={ø}
d) B – C={6,9,15}
e) Ac={1,2,3,4,5,6,7,9,11,13,14,15}
f) B c={1,2,3,4,5,7,8,10,11,13,14}
g) E c ∩ D
E c={1,2,3,4,5,6,7,8,9,10,11}
E c ∩ D={1,5,6,10,11}
E c ∩ D={1,5,6,10,11}
h) B c ∆ Ec
c={1,2,3,4,5,7,8,10,11,13,14}
E c={1,2,3,4,5,6,7,8,9,10,11}
B c ∆ Ec= B c– E c={13,14}∪ E c– B c={3,6,9}
B c ∆ Ec={13,14,3,6,9}
B c ∆ Ec={13,14,3,6,9}
i) B c ∪ E c
B c={1,2,4,5,7,8,10,11,13,14}
E c={1,2,3,4,5,6,7,8,9,10,11}
B c ∪ E c={1,2,3,4,5,7,8,10,11,13,14,3,6,9}
B c ∪ E c={1,2,3,4,5,7,8,10,11,13,14,3,6,9}
j) A ∆ C= A – C ={4,8,10}∪ C-A ={1,2,3,11,13}
A ∆ C={4,8,10,1,2,3,11,13}
k) ( Bc ∪ C)c 3
B c={1,2,4,5,7,8,10,11,13,14}
( Bc ∪ C)={1,2,4,5,7,8,10,11,13,14,3,12}
( Bc ∪ C)c={6,9,15}
L) ( C ∆ D )c
( C ∆ D )=( –D={2,3,12,13}∪ D–C={5,6,10}
( C ∆ D )={2,3,12,13,5,6,10}
( C ∆ D )c={1,4,7,8,9,11,14,15}
( C ∆ D )c={1,4,7,8,9,11,14,15}
2) Si U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} es el conjunto universal y A = {1, 4, 7, 10}, B = {1, 2, 3, 4, 5}, C = {2, 4, 6, 8}:
a) A ∆ B=A–B={7,10}∪ B–A={2,3,5}
A ∆ B={7,10,2,3,5}
b) A-B={7,10}
c) A c={2,3,5,6,8,9}
d) U c= ø e) B ∩ U={1,2,3,4,5}
f) B C ∩ (C − A)
(C − A)={2,6,8}
B C={6,7,8,9,10}
B C ∩ (C − A)={6,7,8,9,10,2,6,8}={6,8}
B C ∩ (C − A)={6,8}
g) (A∩B) c ∪ C
(A∩B) c ∪ C=(A∩B)={1,4}
(A∩B) c={2,3,5,6,7,8,9,10}
A∩B) c ∪ C={2,3,5,6,7,8,9,10,4}
h) B ∩ C={2,4}
i) A ∪ ø={1,4,7,10}
j) A ∩ (B ∆ C)
(B ∆ C)=B−C={1,3,5}∪ C-B={6,8}
(B ∆ C)={1,3,5,6,8}
A ∩ (B ∆ C)={1}
k) (A ∩ B) ∆ C
(A ∩ B)={1,4}
(A ∩ B) ∆ C=(A ∩ B)−C={1}∪ C−(A ∩ B)={2,6,8}
(A ∩ B) ∆ C={1,2,6,8}
(A ∩ B) ∆ C={1,2,6,8}
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