TRABAJO COLABORATIVO UNO ECUACIÓN DIFERENCIAL
Enviado por • 19 de Abril de 2013 • 1.397 Palabras (6 Páginas) • 636 Visitas
TRABAJO COLABORATIVO UNO
MARLY JOHANA FIESCO RIVERA
GRUPO: 10410 – 88
TUTOR:
HAROLD PEREZ
UNIVERSIDAD NACIONAL ABIERTA Y A DISTANCIA - UNAD
PROGRAMA CÁLCULO DIFERENCIAL
TARQUI - HUILA
MARZO 2011
FASE 1
Hallar los 5 primeros términos de las siguientes sucesiones:
Un=(1/(3ⁿ^(+1) ) )ɳ≥1 = ( 1/9 ,1/(27 ) ,1/(81 ) ,1/243 ,1/729 … )
ɳ = 1 1/(3¹⁺¹) = 1/9
ɳ = 2 1/(3 ²⁺¹) = 1/3³ = 1/27
ɳ = 3 1/(3³⁺¹) =1/(3⁴) = 1/81
ɳ = 4 1/(3⁴⁺¹)= 1/(3⁵)= 1/243
ɳ = 5 1/(3⁵⁺¹)= 1/(3⁶)= 1/729
Un = ( 3/(3ⁿ^(-4) ) ) ɳ≥1=( -1, 1.5,0.20,0.125,0.16… )
ɳ = 1 3/(3( 1 )– 4 )= 3/(3-4) = -1/1= - 1
ɳ = 2 3/(3(2)- 4)= 3/(6 -4)= 3/2=1.5
ɳ = 3 1/(3 ( 3 )- 4)= 1/(9 -4)= 1/5=0.20
ɳ = 4 1/(3 ( 4 )- 4)= 1/(12 –4 )= 1/8=0.125
ɳ = 5 1/(2 ( 5 )– 4 )= 1/(30 -4)= 1/6=0.16
Wɳ = ( 1/(n -1) )ⁿ ɳ ≥2= ( 1,0.5,0.33,0.25,0.20… )
ɳ = 1 1/(2 -1)= 1/1=1
ɳ = 2 1/(3 –1 )= 1/2= 0.5
ɳ = 3 1/(4 -1)= 1/(3 ) = 0.33
ɳ = 4 1/(5 –1 )= 1/4 =0.25
ɳ = 5 1/(6 –1 )= 1/5 = 0.20
Identificar el término general dados el primer término y la relación de recurrencia.
U0= 2; Un= Un – 1 +1
U1= U0 +1=2 +1=3
U2 = U 2-1 +1= U1 +1=3 +1=4
U3= U 3 – 1 +2= U2 +1=4 +1=5
Uɳ= ɳ +2
U0=4; Uɳ = ( Uɳ -1)/5
U1= (U1 -1)/5= U0/5¹ = 4/5¹
U2 = ( U2 -1 )/5= ( U1 )/5=4 ( 1/5^2 )
U3 = (U3 -1)/5= U2/5=4 ( 1/5^3 )
U4= ( U4 -1 )/5= ( U3)/5 =4 ( 1/5^4 )
Uɳ=4 ( 1/(5 ) )ⁿ
ɳ ≥0
Wɳ = ( 2/(1 〖^-〗ɳ) ) ɳ≥2
Uɳ + 1 > Uɳ
Uɳ + 1 - Uɳ > 0
2/(1 - ( ɳ +1 ) ) ≥ 2/(1 - ɳ)
2/(1 - ɳ -1 ) ≥ 2/(1 - ɳ)
-2/ɳ ≥ 2/(1 - ɳ)
2/ɳ ≤ 2/(ɳ -1)
2 (ɳ - 1) ≤ 2 ɳ
2ɳ - 2 ≤ 2ɳ
2ɳ - 2ɳ ≤ 2
0 ≤ 2
Xɳ = 2 ⁻ⁿ
Xɳ = 1/(2 ⁿ)
Uɳ + 1 ˂ Uɳ
1/(2ⁿ ⁺¹) ˂ 1/2ⁿ
2 ⁿ ˂ 2ⁿ ⁺ ¹
Vɳ = ( (2ɳ +1)/ɳ )ɳ≥1
M = 1
Uɳ ≤ M
(2ɳ+1)/ɳ - 1
(2ɳ+1-ɳ)/ɳ= (ɳ+1)/ɳ
ɳ+1 ≤ 0 Y ɳ > 0
(ɳ +1)/ɳ ≤1
Para ɳ=0
FASE DOS
...